Ôn thi tốt nghiệp THPT môn Toán - Lớp 12 - Đề thi thử tốt nghiệp THPT môn Toán năm 2025 của Hậu Giang

{"save":1,"level":1,"time":"90","total":34,"point":5,"segment":[{"id":"3875","test_id":"490","question":"<p>Nguy&ecirc;n h&agrave;m c\u1ee7a h&agrave;m s\u1ed1&nbsp;<span class=\"math-tex\">$f(x)=e$<\/span>&nbsp;l&agrave;<\/p>","options":["A.&nbsp;<span class=\"math-tex\">$x^e+C$<\/span>","B.&nbsp;<span class=\"math-tex\">$\\frac{e^2}{2}+C$<\/span>","C.&nbsp;<span class=\"math-tex\">$ex+C$<\/span>","D.&nbsp;<span class=\"math-tex\">$\\frac{ex}{log e} +C$<\/span>"],"correct":"3","answer":"<p>\u0110&aacute;p &aacute;n \u0111&uacute;ng l&agrave;:&nbsp;<span style=\"color:#16a085;\"><strong>C.&nbsp;<span class=\"math-tex\">$ex+C$<\/span>.<\/strong><\/span><\/p><p>Ta c&oacute;:&nbsp;<span class=\"math-tex\">$\\displaystyle \\int f(x)dx=\\int edx=ex + C$<\/span>.<\/p>","type":"choose","user_id":"126","test":"0","date":"2025-05-14 14:51:07"},{"id":"3876","test_id":"490","question":"<p>Cho h&igrave;nh ph\u1eb3ng (H) gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb h&agrave;m s\u1ed1 <span class=\"math-tex\">$y=x^2-4x$<\/span>, tr\u1ee5c ho&agrave;nh v&agrave; hai \u0111\u01b0\u1eddng th\u1eb3ng x = 1 v&agrave; x = 3. Kh\u1ed1i tr&ograve;n xoay \u0111\u01b0\u1ee3c t\u1ea1o th&agrave;nh khi quay h&igrave;nh ph\u1eb3ng (H)&nbsp;quanh tr\u1ee5c Ox c&oacute; th\u1ec3 t&iacute;ch l&agrave;<\/p>","options":["<strong>A.<\/strong>&nbsp;<span class=\"math-tex\">$V=\\dfrac{406}{15}$<\/span>","<strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$V=\\dfrac{406}{15}\\pi$<\/span>","<strong>C.<\/strong>&nbsp;<span class=\"math-tex\">$V=\\dfrac{22}{3}\\pi$<\/span>","<strong>D.<\/strong>&nbsp;<span class=\"math-tex\">$V=\\dfrac{512}{15}\\pi$<\/span>"],"correct":"2","answer":"<p>\u0110&aacute;p &aacute;n \u0111&uacute;ng l&agrave;:&nbsp;<span style=\"color:#16a085;\"><strong>B.&nbsp;<span class=\"math-tex\">$V=\\dfrac{406}{15}\\pi$<\/span>.<\/strong><\/span><\/p><p>Th\u1ec3&nbsp;t&iacute;ch c\u1ee7a kh\u1ed1i tr&ograve;n xoay l&agrave;<\/p><p><span class=\"math-tex\">$V=\\pi\\displaystyle\\int\\limits_{1}^{3}(x^2-4x)^2dx=\\pi\\displaystyle\\int\\limits_{1}^{3}(x^4-8x^3+16x^2)dx=\\pi.\\bigg(\\dfrac{x^5}{5}-2x^4+\\dfrac{16}{3}x^3\\bigg)\\bigg|_1^3=\\dfrac{406}{15}\\pi$<\/span>.<\/p>","type":"choose","user_id":"126","test":"1","date":"2025-05-14 14:55:38"}]}