Ôn thi tốt nghiệp THPT môn Toán - Lớp 12 - Đề thi thử tốt nghiệp THPT môn Toán năm 2025 của Hưng Yên
{"save":1,"level":1,"time":"90","total":34,"point":5,"segment":[{"id":"3943","test_id":"492","question":"<p>Tìm nguyên hàm c\u1ee7a hàm s\u1ed1 <span class=\"math-tex\">$f(x)=\\dfrac{1}{5x-12}$<\/span><\/p>","options":["A. <span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=\\dfrac{1}{5}\\ln|12-5x|+C$<\/span>","B. <span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=-\\dfrac{1}{5}\\ln|5x-12|+C$<\/span>","C. <span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=5\\ln|5x-12|+C$<\/span>","D. <span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=\\ln|5x-12|+C$<\/span>"],"correct":"1","answer":"<p>\u0110áp án \u0111úng là: <span style=\"color:#16a085;\"><strong>A. <span class=\"math-tex\">$\\displaystyle\\int\\frac{dx}{5x-12}=\\frac{1}{5}\\ln|12-5x|+C$<\/span>.<\/strong><\/span><\/p><p>Ta có: <span class=\"math-tex\">$\\displaystyle\\int f(x)dx=\\int\\dfrac{1}{5x-12}dx=\\dfrac{1}{5}\\ln(5x-12)+C$<\/span>.<\/p>","type":"choose","user_id":"126","test":"3","date":"2025-05-16 11:22:53"},{"id":"3944","test_id":"492","question":"<p>Trong không gian Oxyz, ph\u01b0\u01a1ng trình nào d\u01b0\u1edbi \u0111ây là ph\u01b0\u01a1ng trình chính t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng <span class=\"math-tex\">$d: \\begin{cases} x=-1+2t \\\\ y=3t \\\\ z=-3+t \\end{cases}$<\/span> ?<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z-3}{-2}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{x-1}{1}=\\dfrac{y}{3}=\\dfrac{z+3}{-2}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y-3}{3}=\\dfrac{z+3}{1}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z+3}{1}$<\/span>"],"correct":"4","answer":"<p>\u0110áp án \u0111úng là: <span style=\"color:#16a085;\"><strong>D. <span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z+3}{1}$<\/span>.<\/strong><\/span><\/p><p>\u0110\u01b0\u1eddng th\u1eb3ng d \u0111i qua \u0111i\u1ec3m <span class=\"math-tex\">$(-1;0;-3)$<\/span> và có m\u1ed9t VTCP là <span class=\"math-tex\">$\\overrightarrow{u}=(2;3;1)$<\/span> nên có ph\u01b0\u01a1ng trình chình t\u1eafc là<\/p><p><span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z+3}{1}$<\/span>.<\/p>","type":"choose","user_id":"126","test":"1","date":"2025-05-16 11:54:37"}]}