Ôn thi tốt nghiệp THPT môn Vật lý- Lớp 12 - Đề tham khảo tốt nghiệp THPT môn Vật lí năm 2025 của Vĩnh Phúc (mã 204)
{"save":1,"level":1,"time":"50","total":40,"point":5,"segment":[{"id":"4720","test_id":"523","question":"<p>M\u1ed9t l\u01b0\u1ee3ng khí lí t\u01b0\u1edfng \u1edf nhi\u1ec7t \u0111\u1ed9 300 K có \u0111\u1ed9ng n\u0103ng t\u1ecbnh ti\u1ebfn trung bình c\u1ee7a m\u1ed7i phân t\u1eed là <span class=\"math-tex\">$\\overline{E_d}$<\/span>. N\u1ebfu nhi\u1ec7t \u0111\u1ed9 t\u0103ng lên \u0111\u1ebfn 600 K thì \u0111\u1ed9ng n\u0103ng t\u1ecbnh ti\u1ebfn trung bình m\u1ed7i phân t\u1eed s\u1ebd là:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$4\\overline{E_d}$<\/span>.","<strong>B.<\/strong> <span class=\"math-tex\">$\\overline{E_d}$<\/span>.","<strong>C.<\/strong> <span class=\"math-tex\">$2\\overline{E_d}$<\/span>.","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{1}{2}\\overline{E_d}$<\/span>."],"correct":"3","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$2\\overline{E_d}$<\/span>.<\/span><\/p><p>Ta có: <span class=\"math-tex\">$\\overline{E_d}=\\dfrac{3}{2}kT$<\/span> ⇒ <span class=\"math-tex\">$\\dfrac{E^\\prime_d}{E_d}=\\dfrac{T^\\prime}{T}=\\dfrac{600}{300}=2$<\/span> ⇒ <span class=\"math-tex\">$E^\\prime_d=2E_d$<\/span>.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-07 08:14:08"},{"id":"4723","test_id":"523","question":"<p>B\u1ea1n A mu\u1ed1n \u0111un sôi 1,5 lít n\u01b0\u1edbc b\u1eb1ng b\u1ebfp gas. Do s\u01a1 su\u1ea5t nên b\u1ea1n quên không t\u1eaft b\u1ebfp khi n\u01b0\u1edbc sôi. Bi\u1ebft nhi\u1ec7t hóa h\u01a1i riêng c\u1ee7a n\u01b0\u1edbc là 2,26.10<sup>6<\/sup> J\/kg và kh\u1ed1i l\u01b0\u1ee3ng riêng c\u1ee7a n\u01b0\u1edbc là 10<sup>3<\/sup> kg\/m<sup>3<\/sup>. Nhi\u1ec7t l\u01b0\u1ee3ng \u0111ã làm hóa h\u01a1i 1 lít n\u01b0\u1edbc trong \u1ea5m \u1edf nhi\u1ec7t \u0111\u1ed9 sôi do s\u01a1 su\u1ea5t \u0111ó b\u1eb1ng:<\/p>","options":["<strong>A.<\/strong> 3,45.10<sup>6<\/sup> J\/kg.","<strong>B.<\/strong> 4,52.10<sup>6<\/sup> J\/kg.","<strong>C.<\/strong> 2,26.10<sup>6<\/sup> J\/kg.","<strong>D.<\/strong> 1,13.10<sup>6<\/sup> J\/kg."],"correct":"3","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> 2,26.10<sup>6<\/sup> J\/kg.<\/span><\/p><p>m = VD = 1.10<sup>–3<\/sup> . 10<sup>3<\/sup> = 1 (kg).<\/p><p>Q = mL = 1 . 2,26.10<sup>6<\/sup> = 2,26.10<sup>6<\/sup> (J\/kg).<\/p><p>V\u1eady nhi\u1ec7t l\u01b0\u1ee3ng \u0111ã làm hóa h\u01a1i 1 lít n\u01b0\u1edbc trong \u1ea5m \u1edf nhi\u1ec7t \u0111\u1ed9 sôi do s\u01a1 su\u1ea5t \u0111ó b\u1eb1ng 2,26.10<sup>6<\/sup> J\/kg.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-07 08:18:02"}]}