Ôn thi tốt nghiệp THPT môn Vật lý- Lớp 12 - Đề tham khảo tốt nghiệp THPT môn Vật lí năm 2025 của Nam Định

{"save":1,"level":1,"time":"50","total":40,"point":5,"segment":[{"id":"4925","test_id":"526","question":"<p>Bi\u1ebft nhi\u1ec7t n&oacute;ng ch\u1ea3y ri&ecirc;ng c\u1ee7a n\u01b0\u1edbc \u0111&aacute; \u1edf 0&deg;C l&agrave;&nbsp;3,3.10<sup>5<\/sup> J\/kg. Nhi\u1ec7t l\u01b0\u1ee3ng c\u1ea7n cung c\u1ea5p \u0111\u1ec3 30 g&nbsp;n\u01b0\u1edbc \u0111&aacute; tan ch\u1ea3y ho&agrave;n to&agrave;n \u1edf 0&deg;C b\u1eb1ng:<\/p>","options":["<strong>A.<\/strong>&nbsp;1,1.10<sup>4<\/sup> J.","<strong>B.<\/strong>&nbsp;9,9.10<sup>3<\/sup> J.","<strong>C.<\/strong>&nbsp;9,9.10<sup>6<\/sup> J.","<strong>D.<\/strong>&nbsp;1,1.10<sup>7<\/sup> J."],"correct":"2","answer":"<p>Ch\u1ecdn<span style=\"color:#16a085;\">&nbsp;<strong>B.<\/strong>&nbsp;9,9.10<sup>3<\/sup> J.<\/span><\/p><p>Nhi\u1ec7t l\u01b0\u1ee3ng c\u1ea7n cung c\u1ea5p \u0111\u1ec3 30 g&nbsp;n\u01b0\u1edbc \u0111&aacute; tan ch\u1ea3y ho&agrave;n to&agrave;n \u1edf 0&deg;C l&agrave;:<\/p><p>Q = m&lambda;&nbsp;= 0,03 . 3,3.10<sup>5<\/sup>&nbsp;= 9,9.10<sup>3<\/sup>&nbsp;(J).<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-08 14:45:27"},{"id":"4929","test_id":"526","question":"<p>Khi nhi\u1ec7t \u0111\u1ed9 c\u1ee7a m\u1ed9t l\u01b0\u1ee3ng kh&iacute; l&iacute; t\u01b0\u1edfng t\u0103ng t\u1eeb 20,0&deg;C&nbsp;l&ecirc;n nhi\u1ec7t \u0111\u1ed9 40,0&deg;C th&igrave; \u0111\u1ed9ng n\u0103ng trung&nbsp;b&igrave;nh c\u1ee7a c&aacute;c ph&acirc;n t\u1eed kh&iacute; t\u0103ng th&ecirc;m bao nhi&ecirc;u ph\u1ea7n tr\u0103m so v\u1edbi l&uacute;c \u0111\u1ea7u?<\/p>","options":["<strong>A.<\/strong>&nbsp;6,83%.","<strong>B.<\/strong>&nbsp;200%.","<strong>C.<\/strong>&nbsp;100%.","<strong>D.<\/strong>&nbsp;46,6%."],"correct":"1","answer":"<p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>A.<\/strong>&nbsp;6,83%.<\/span><\/p><p><span class=\"math-tex\">$W_\u0111\\sim T$<\/span>&nbsp;&rArr;&nbsp;<span class=\"math-tex\">$\\dfrac{W_{\u01112}}{W_{\u01111}}=\\dfrac{T_2}{T_1}=\\dfrac{40+273}{20+273}\\approx1,0683=106,83\\%= 100\\%+6,83\\%$<\/span><\/p><p>V\u1eady&nbsp;\u0111\u1ed9ng n\u0103ng trung&nbsp;b&igrave;nh c\u1ee7a c&aacute;c ph&acirc;n t\u1eed kh&iacute; t\u0103ng th&ecirc;m 6,83% so v\u1edbi l&uacute;c \u0111\u1ea7u.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-08 14:50:03"}]}