{"common":{"save":0,"post_id":"7288","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5497","post_id":"7288","mon_id":"1158924","chapter_id":"1159168","question":"<p>\u0110\u1ed9 pH c\u1ee7a m\u1ed9t dung d\u1ecbch \u0111\u01b0\u1ee3c t&iacute;nh theo c&ocirc;ng th\u1ee9c&nbsp;<span class=\"math-tex\">$pH=-\\log[H^+]$<\/span>&nbsp;trong \u0111&oacute;&nbsp;<span class=\"math-tex\">$[H^+]$<\/span>&nbsp;l&agrave; n\u1ed3ng \u0111\u1ed9&nbsp;<span class=\"math-tex\">$H^+$<\/span>&nbsp;c\u1ee7a dung d\u1ecbch \u0111&oacute; t&iacute;nh b\u1eb1ng mol\/L. N\u1ed3ng \u0111\u1ed9&nbsp;<span class=\"math-tex\">$H^+$<\/span>&nbsp;trong dung d\u1ecbch cho bi\u1ebft \u0111\u1ed9 acid c\u1ee7a dung d\u1ecbch \u0111&oacute;. Dung d\u1ecbch acid A c&oacute; \u0111\u1ed9 pH b\u1eb1ng 1,9. Bi\u1ebft n\u1ed3ng \u0111\u1ed9&nbsp;<span class=\"math-tex\">$H^+$<\/span>&nbsp;trong dung d\u1ecbch acid A cao h\u01a1n trong dung d\u1ecbch acid B l&agrave;&nbsp;<span class=\"math-tex\">$10^{0,6}$<\/span>&nbsp;l\u1ea7n. T&iacute;nh n\u1ed3ng \u0111\u1ed9&nbsp;<span class=\"math-tex\">$H^+$<\/span>&nbsp;trong dung d\u1ecbch acid B.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$10^{2,5}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$10^{-2,5}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$10^{25}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$10^{-25}$<\/span>"],"correct":"2","level":"3","hint":"","answer":"<p>Dung d\u1ecbch acid A c&oacute; n\u1ed3ng \u0111\u1ed9&nbsp;<span class=\"math-tex\">$H^+$<\/span>&nbsp;l&agrave;&nbsp;<span class=\"math-tex\">$[H^+]_A=10^{-1,9}$<\/span>.<\/p><p>Dung d\u1ecbch acid B c&oacute; n\u1ed3ng \u0111\u1ed9&nbsp;<span class=\"math-tex\">$H^+$<\/span>&nbsp;l&agrave;<\/p><p><span class=\"math-tex\">$[H^+]_A=10^{0,6}.[H^+]_B$<\/span>&nbsp;&hArr;&nbsp;<span class=\"math-tex\">$[H^+]_B=\\dfrac{10^{-1,9}}{10^{0,6}}=10^{-2,5}$<\/span>.<\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$10^{-2,5}$<\/span>.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-04-07 06:15:53","option_type":"math","len":0},{"id":"5499","post_id":"7288","mon_id":"1158924","chapter_id":"1159168","question":"<p>Gi\u1ea3 s\u1eed qu&aacute; tr&igrave;nh nu&ocirc;i c&aacute;y vi khu\u1ea9n tu&acirc;n theo quy lu\u1eadt t\u0103ng tr\u01b0\u1edfng t\u1ef1 do. Khi \u0111&oacute;, n\u1ebfu g\u1ecdi&nbsp;<span class=\"math-tex\">$N_o$<\/span>&nbsp;l&agrave; s\u1ed1 l\u01b0\u1ee3ng vi khu\u1ea9n ban \u0111\u1ea7u v&agrave;&nbsp;<span class=\"math-tex\">$N(t) $<\/span>&nbsp;l&agrave; s\u1ed1 l\u01b0\u1ee3ng vi khu\u1ea9n sau&nbsp;<span class=\"math-tex\">$t$<\/span>&nbsp;gi\u1edd th&igrave; ta c&oacute;&nbsp;<span class=\"math-tex\">$N(t)=N_o.e^{rt}$<\/span>, trong \u0111&oacute;&nbsp;<span class=\"math-tex\">$r$<\/span>&nbsp;l&agrave; t\u1ec9 l\u1ec7 t\u0103ng tr\u01b0\u1edfng vi khu\u1ea9n m\u1ed7i gi\u1edd. Gi\u1ea3 s\u1eed ban \u0111\u1ea7u c&oacute; 500 con vi khu\u1ea9n v&agrave; sau m\u1ed9t gi\u1edd t\u0103ng l&ecirc;n 800 con. T&iacute;nh s\u1ed1 l\u01b0\u1ee3ng vi khu\u1ea9n sau 3 gi\u1edd.<\/p>","options":["<strong>A.<\/strong> 2048 con","<strong>B.<\/strong> 3276 con","<strong>C.<\/strong> 3275 con","<strong>D.<\/strong> 2084 con"],"correct":"1","level":"3","hint":"","answer":"<p>Ban \u0111\u1ea7u c&oacute; 500 con vi khu\u1ea9n, sau 1 gi\u1edd t\u0103ng l&ecirc;n 800 con n&ecirc;n ta c&oacute;<\/p><p><span class=\"math-tex\">$500.e^{r}=800$<\/span>&nbsp;&hArr;&nbsp;<span class=\"math-tex\">$e^r=1,6$<\/span>&nbsp;&hArr;&nbsp;<span class=\"math-tex\">$r=\\ln1,6$<\/span>.<\/p><p>S\u1ed1 l\u01b0\u1ee3ng vi khu\u1ea9n t\u0103ng l&ecirc;n sau 3 gi\u1edd l&agrave;&nbsp;<span class=\"math-tex\">$N(3)=500.e^{3.\\ln1,6}=2048$<\/span>&nbsp;con.<\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>A.<\/strong> 2048 con.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-04-07 06:22:26","option_type":"txt","len":1},{"id":"5502","post_id":"7288","mon_id":"1158924","chapter_id":"1159168","question":"<p>Cho&nbsp;<span class=\"math-tex\">$\\log_{ab}b=3$<\/span>, a &gt; 0, b &gt; 0, ab&nbsp;<span class=\"math-tex\">$\\ne$<\/span>&nbsp;1. T&iacute;nh&nbsp;<span class=\"math-tex\">$\\log_\\sqrt{ab}\\bigg(\\dfrac{a}{b^2}\\bigg)$<\/span>.<\/p>","options":["<strong>A.<\/strong> 5","<strong>B.<\/strong> &ndash;4","<strong>C.<\/strong> &ndash;10","<strong>D.<\/strong> &ndash;16"],"correct":"4","level":"3","hint":"","answer":"<p>Ta c&oacute;&nbsp;<span class=\"math-tex\">$\\log_{ab}b=3$<\/span>&nbsp;<\/p><p>&hArr;&nbsp;<span class=\"math-tex\">$\\log_bab=\\dfrac{1}{3}$<\/span><\/p><p>&hArr;&nbsp;<span class=\"math-tex\">$\\log_ba+1=\\dfrac{1}{3}$<\/span><\/p><p>&hArr;&nbsp;<span class=\"math-tex\">$\\log_ba=-\\dfrac{2}{3}$<\/span>&nbsp;&rArr;&nbsp;<span class=\"math-tex\">$\\log_ab=-\\dfrac{3}{2}$<\/span>.<\/p><p><span class=\"math-tex\">$\\log_\\sqrt{ab}\\bigg(\\dfrac{a}{b^2}\\bigg)$<\/span>&nbsp;<span class=\"math-tex\">$=2(\\log_{ab}a-\\log_{ab}b^2)$<\/span><span class=\"math-tex\">$=\u200b\u200b\\dfrac{2}{\\log_aab}-4\\log_{ab}b$<\/span><span class=\"math-tex\">$=\\dfrac{2}{1+\\log_ab}-4.3$<\/span><span class=\"math-tex\">$=\\dfrac{2}{1-\\dfrac{3}{2}}-12=-16$<\/span>.<\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>D.<\/strong>&nbsp;&ndash;16.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-04-07 06:35:18","option_type":"txt","len":1}]}