{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["1"],["16"]]],"list":[{"point":10,"width":50,"ques":"Cho $A = \\dfrac{\\left( 9\\dfrac{3}{4} : 5,2 + 3,4 . 2\\dfrac{7}{34} \\right) : 1\\dfrac{9}{16}}{0,31 . 8\\dfrac{2}{5} - 5,61 : 27\\dfrac{1}{2}}$ <br\/><br\/> 2,5% c\u1ee7a A l\u00e0: <div class=\"frac123\"><div class=\"ts\">_input_<\/div><div class=\"ms\">_input_<\/div><\/div>","hint":"R\u00fat g\u1ecdn A r\u1ed3i t\u00ecm 2,5% c\u1ee7a A","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Vi\u1ebft c\u00e1c h\u1ed7n s\u1ed1 v\u00e0 s\u1ed1 th\u1eadp ph\u00e2n d\u01b0\u1edbi d\u1ea1ng ph\u00e2n s\u1ed1 <br\/> <b> B\u01b0\u1edbc 2: <\/b> R\u00fat g\u1ecdn A <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ecm 2,5% c\u1ee7a A <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $ \\begin{align*} & A = \\dfrac{\\left( 9\\dfrac{3}{4} : 5,2 + 3,4 . 2\\dfrac{7}{34} \\right) : 1\\dfrac{9}{16}}{0,31 . 8\\dfrac{2}{5} - 5,61 : 27\\dfrac{1}{2}} \\\\ & = \\dfrac{ \\left( \\dfrac{39}{4} : \\dfrac{52}{10} + \\dfrac{34}{10} . \\dfrac{75}{34} \\right) : \\dfrac{25}{16}}{\\dfrac{31}{100} . \\dfrac{42}{5} - \\dfrac{561}{100} : \\dfrac{55}{2}} \\\\ &= \\dfrac{ \\left( \\dfrac{39}{4} . \\dfrac{5}{26} + \\dfrac{15}{2} \\right) . \\dfrac{16}{25}}{\\dfrac{651}{250} - \\dfrac{561}{100} . \\dfrac{2}{55}} \\\\ &= \\dfrac{\\left( \\dfrac{15}{8} + \\dfrac{15}{2} \\right) . \\dfrac{16}{25}}{ \\dfrac{651}{250} - \\dfrac{51}{250}} \\\\ &= \\dfrac{ \\dfrac{75}{8} . \\dfrac{16}{25} }{\\dfrac{12}{5}} \\\\ &= \\dfrac{6}{\\dfrac{12}{5}} = \\dfrac{5}{2} \\end{align*} $ <br\/> $2,5 \\% . A = \\dfrac{25}{1000} . \\dfrac{5}{2} = \\dfrac{1}{16}$ <br\/> <span class='basic_green'> <i> Nh\u1eadn x\u00e9t: Mu\u1ed1n t\u00ecm gi\u00e1 tr\u1ecb ph\u00e2n s\u1ed1 c\u1ee7a m\u1ed9t ph\u00e2n s\u1ed1 A, tr\u01b0\u1edbc ti\u00ean ta r\u00fat g\u1ecdn A r\u1ed3i m\u1edbi t\u00ecm gi\u00e1 ph\u00e2n s\u1ed1 c\u1ee7a A <\/i> <\/span> "}]}],"id_ques":1851},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["69"],["100"]]],"list":[{"point":10,"width":50,"ques":" Cho $M = \\dfrac{3 : \\dfrac{2}{5} - 0,09 : \\left( 0,15 : 2\\dfrac{1}{2} \\right)}{0,32 . 6 + 0,03 - (5,3 - 3,88) + 0,67}$ <br\/><br\/> $N = \\dfrac{(2,1 - 1,965) : (1,2 . 0,045)}{0,00325 : 0,013} - \\dfrac{1 : 0,25}{1,6 . 0,625}$ <br\/> <br\/> $12\\%$ c\u1ee7a $\\dfrac{3}{4} . M + \\dfrac{1}{3} . N$ l\u00e0: <div class=\"frac123\"><div class=\"ts\">_input_<\/div><div class=\"ms\">_input_<\/div><\/div>","hint":" R\u00fat g\u1ecdn M, N r\u1ed3i t\u00ednh","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Kh\u00e9o l\u00e9o chuy\u1ec3n gi\u1eefa ph\u00e2n s\u1ed1, h\u1ed7n s\u1ed1 v\u1edbi s\u1ed1 th\u1eadp ph\u00e2n \u0111\u1ec3 r\u00fat g\u1ecdn M, N <br\/> <b> B\u01b0\u1edbc 2: <\/b>T\u00ednh $\\dfrac{3}{4}. M + \\dfrac{1}{3} . N$ <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh 12% c\u1ee7a $\\dfrac{3}{4} . M + \\dfrac{1}{3} . N$ <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $ \\begin{align*} &M = \\dfrac{3 : \\dfrac{2}{5} - 0,09 : \\left( 0,15 : 2\\dfrac{1}{2} \\right)}{0,32 . 6 + 0,03 - (5,3 - 3,88) + 0,67} \\\\ &= \\dfrac{3 . \\dfrac{5}{2} - \\dfrac{9}{100} : \\left( \\dfrac{15}{100} . \\dfrac{2}{5} \\right)}{1,92 + 0,03 - 1,42 + 0,67} \\\\ &= \\dfrac{\\dfrac{15}{2} - \\dfrac{9}{100} : \\dfrac{3}{50}}{1,92 - 1,42 + 0,03 + 0,67} \\\\ &= \\dfrac{\\dfrac{15}{2} - \\dfrac{3}{2}}{0,5 + 0,7} \\\\ &= \\dfrac{6}{1,2} = \\dfrac{6}{\\dfrac{12}{10}} = 5 \\end{align*} $ <br\/> $ \\begin{align*} &N = \\dfrac{(2,1 - 1,965) : (1,2 . 0,045)}{0,00325 : 0,013} - \\dfrac{1 : 0,25}{1,6 . 0,625} \\\\ &= \\dfrac{0,135 : 0,054 }{0,25} - \\dfrac{4}{1} \\\\ &= \\dfrac{2,5}{0,25} - 4 \\\\ &= 10 - 4 = 6 \\end{align*} $ <br\/> $\\dfrac{3}{4} . M + \\dfrac{1}{3} . N = \\dfrac{3}{4} . 5 + \\dfrac{1}{3} . 6 = \\dfrac{15}{4} + 2 = \\dfrac{23}{4} = 5,75$ <br\/> 12% c\u1ee7a $\\dfrac{3}{4} . M + \\dfrac{1}{3} . N$ l\u00e0: 12% . 5,75 = 0,69 = $\\dfrac{69}{100}$ "}]}],"id_ques":1852},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["105101005","105101005,01"]]],"list":[{"point":10,"width":100,"type_input":"","ques":"M\u1ed9t ng\u01b0\u1eddi g\u1eedi ti\u1ebft ki\u1ec7m 100 tri\u1ec7u \u0111\u1ed3ng v\u00e0o ng\u00e2n h\u00e0ng theo th\u1ec3 th\u1ee9c c\u00f3 k\u00ec h\u1ea1n 1 n\u0103m v\u1edbi l\u00e3i su\u1ea5t 1% m\u1ed9t n\u0103m. H\u1ecfi sau 5 n\u0103m ng\u01b0\u1eddi \u0111\u00f3 m\u1edbi r\u00fat ti\u1ec1n k\u1ec3 t\u1eeb ng\u00e0y g\u1eedi th\u00ec s\u1ed1 ti\u1ec1n c\u1ea3 v\u1ed1n l\u1eabn l\u00e3i l\u00e0 bao nhi\u00eau? <br\/>\u0110\u00e1p s\u1ed1: _input_ \u0111\u1ed3ng","hint":"sau m\u1ed7i n\u0103m th\u00ec s\u1ed1 ti\u1ec1n l\u00e3i l\u1ea1i \u0111\u01b0\u1ee3c c\u1ed9ng d\u1ed3n v\u00e0o ti\u1ec1n g\u1ed1c","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh s\u1ed1 c\u1ea3 g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 1 n\u0103m <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh c\u1ea3 g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 2 n\u0103m <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh s\u1ed1 ti\u1ec1n g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 3 n\u0103m <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh s\u1ed1 ti\u1ec1n g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 4 n\u0103m <br\/> <b> B\u01b0\u1edbc 5: <\/b> T\u00ednh s\u1ed1 ti\u1ec1n g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 5 n\u0103m <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> S\u1ed1 ti\u1ec1n g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 1 n\u0103m l\u00e0: <br\/> 100 000 000 + 1% . 100 000 000 = 101 000 000 (\u0111\u1ed3ng) <br\/> S\u1ed1 ti\u1ec1n g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 2 n\u0103m: <br\/> 101 000 000 + 1% . 101 000 000 = 102 010 000 (\u0111\u1ed3ng) <br\/> S\u1ed1 ti\u1ec1n g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 3 n\u0103m l\u00e0: <br\/> 102 010 000 + 1% . 102 010 000 = 103 030 100 (\u0111\u1ed3ng) <br\/> S\u1ed1 ti\u1ec1n g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 4 n\u0103m l\u00e0: <br\/> 103 030 100 + 1% . 103 030 100 = 104 060 401 (\u0111\u1ed3ng) <br\/> S\u1ed1 ti\u1ec1n c\u1ea3 g\u1ed1c v\u00e0 l\u00e3i ng\u01b0\u1eddi \u0111\u00f3 nh\u1eadn \u0111\u01b0\u1ee3c sau 5 n\u0103m l\u00e0: <br\/> 104 060 401 + 1% . 104 060 401 = 105 101 005,01 (\u0111\u1ed3ng) <br\/> \u0110\u00e1p s\u1ed1: 105 101 005,01 \u0111\u1ed3ng (c\u00f3 th\u1ec3 l\u00e0m tr\u00f2n s\u1ed1 th\u00e0nh 105 101 005 \u0111\u1ed3ng) <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 105101005 ho\u1eb7c 105101005,01<\/span> <br\/> <span class='basic_green'><i> Nh\u1eadn x\u00e9t: \u1ede b\u00e0i to\u00e1n n\u00e0y h\u1ecdc sinh hay m\u1eafc sai l\u1ea7m l\u00e0 t\u00ednh % c\u1ee7a 1 n\u0103m r\u1ed3i \u0111em nh\u00e2n v\u1edbi 5 \u0111\u1ec3 t\u00ednh s\u1ed1 ti\u1ec1n l\u00e3i c\u1ee7a 5 n\u0103m <\/i> <\/span> "}]}],"id_ques":1853},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["350"]]],"list":[{"point":10,"width":50,"type_input":"","ques":"B\u1ea1n Thu \u0111\u1ecdc m\u1ed9t cu\u1ed1n s\u00e1ch trong 4 ng\u00e0y. Ng\u00e0y th\u1ee9 nh\u1ea5t Thu \u0111\u1ecdc \u0111\u01b0\u1ee3c $\\dfrac{1}{5}$ cu\u1ed1n s\u00e1ch v\u00e0 10 trang. Ng\u00e0y th\u1ee9 hai, Thu \u0111\u1ecdc \u0111\u01b0\u1ee3c $\\dfrac{4}{9}$ s\u1ed1 trang c\u00f2n l\u1ea1i v\u00e0 10 trang. Ng\u00e0y th\u1ee9 ba, Thu \u0111\u1ecdc \u0111\u01b0\u1ee3c $\\dfrac{2}{7}$ s\u1ed1 trang c\u00f2n l\u1ea1i v\u00e0 10 trang. Ng\u00e0y th\u1ee9 t\u01b0, Thu \u0111\u1ecdc \u0111\u01b0\u1ee3c $\\dfrac{8}{9}$ s\u1ed1 trang c\u00f2n l\u1ea1i v\u00e0 10 trang cu\u1ed1i c\u00f9ng. H\u1ecfi cu\u1ed1n s\u00e1ch Thu \u0111\u1ecdc c\u00f3 bao nhi\u00eau trang? <br\/>\u0110\u00e1p s\u1ed1: _input_ trang","hint":"S\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p t\u00ednh ng\u01b0\u1ee3c t\u1eeb cu\u1ed1i l\u00ean","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n trang s\u00e1ch c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 \u1ee9ng v\u1edbi 10 trang <br\/> T\u00ednh s\u1ed1 trang s\u00e1ch c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n trang s\u00e1ch c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 2, \u1ee9ng v\u1edbi (s\u1ed1 trang \u0111\u1ecdc ng\u00e0y th\u1ee9 4 + 10 trang) <br\/> T\u00ednh s\u1ed1 trang s\u00e1ch c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 hai <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n trang s\u00e1ch c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t, \u1ee9ng v\u1edbi (s\u1ed1 trang \u0111\u1ecdc ng\u00e0y th\u1ee9 3 + 10 trang) <br\/> T\u00ednh s\u1ed1 trang c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n trang s\u00e1ch \u1ee9ng v\u1edbi (s\u1ed1 trang c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t + 10 trang) <br\/> T\u00ednh s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> 10 trang s\u00e1ch \u1ee9ng v\u1edbi $1 - \\dfrac{8}{9} = \\dfrac{1}{9}$ s\u1ed1 trang \u0111\u1ecdc ng\u00e0y th\u1ee9 t\u01b0 <br\/> S\u1ed1 trang s\u00e1ch c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 l\u00e0: <br\/> $10 : \\dfrac{1}{9} = 90$ (trang) <br\/> (90 + 10) trang l\u00e0 $1 - \\dfrac{2}{7} = \\dfrac{5}{7}$ s\u1ed1 trang c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 hai <br\/> V\u1eady s\u1ed1 trang c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 hai l\u00e0: <br\/> $(90 + 10) : \\dfrac{5}{7} = 140$ (trang) <br\/> (140 + 10) trang l\u00e0 $1 - \\dfrac{4}{9} = \\dfrac{5}{9}$ s\u1ed1 trang c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t <br\/> V\u1eady s\u1ed1 trang c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0: <br\/> $(140 + 10) : \\dfrac{5}{9} = 270$ (trang) <br\/> (270 + 10) trang l\u00e0 $1 - \\dfrac{1}{5} = \\dfrac{4}{5}$ s\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch <br\/> S\u1ed1 trang c\u1ee7a cu\u1ed1n s\u00e1ch Thu \u0111\u00e3 \u0111\u1ecdc l\u00e0: <br\/> $(270 + 10) : \\dfrac{4}{5} = 350$ (trang) <br\/> \u0110\u00e1p s\u1ed1: 350 trang <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 350 <\/span> "}]}],"id_ques":1854},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["78"]]],"list":[{"point":10,"width":50,"type_input":"","ques":"M\u1ed9t c\u1eeda h\u00e0ng b\u00e1n m\u1ed9t t\u1ea5m v\u1ea3i trong 4 ng\u00e0y. Ng\u00e0y th\u1ee9 nh\u1ea5t b\u00e1n $\\dfrac{1}{6}$ t\u1ea5m v\u1ea3i v\u00e0 5m; ng\u00e0y th\u1ee9 hai b\u00e1n 20% s\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i v\u00e0 10m; ng\u00e0y th\u1ee9 ba b\u00e1n 25% s\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i v\u00e0 9m; ng\u00e0y th\u1ee9 t\u01b0 b\u00e1n $\\dfrac{1}{3}$ s\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i. Cu\u1ed1i c\u00f9ng c\u00f2n 13m. T\u00ednh chi\u1ec1u d\u00e0i c\u1ee7a t\u1ea5m v\u1ea3i. <br\/> \u0110\u00e1p s\u1ed1: _input_ m\u00e9t","hint":"S\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p t\u00ednh ng\u01b0\u1ee3c t\u1eeb cu\u1ed1i l\u00ean","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n t\u1ea5m v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 \u1ee9ng v\u1edbi 13m <br\/> T\u00ednh s\u1ed1 m\u00e9t c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n t\u1ea5m v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 2, \u1ee9ng v\u1edbi (s\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 + 9m) <br\/> T\u00ednh s\u1ed1 m\u00e9t v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 hai <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n t\u1ea5m v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t, \u1ee9ng v\u1edbi (s\u1ed1 m\u00e9t v\u1ea3i b\u00e1n ng\u00e0y th\u1ee9 3 + 10m) <br\/> T\u00ednh s\u1ed1 m\u00e9t v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n c\u1ee7a t\u1ea5m v\u1ea3i \u1ee9ng v\u1edbi (s\u1ed1 m\u00e9t v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t + 5m) <br\/> T\u00ednh chi\u1ec1u d\u00e0i c\u1ee7a t\u1ea5m v\u1ea3i <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> 13m v\u1ea3i cu\u1ed1i c\u00f9ng \u1ee9ng v\u1edbi $1 - \\dfrac{1}{3} = \\dfrac{2}{3}$ s\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 <br\/> S\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 3 l\u00e0: <br\/> $13 : \\dfrac{2}{3} = \\dfrac{39}{2}$ (m) <br\/> $\\left( 9 + \\dfrac{39}{2} \\right)$ m\u00e9t v\u1ea3i \u1ee9ng v\u1edbi $100\\% - 25\\% = 75\\%$ s\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 2 <br\/> S\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 2 l\u00e0: <br\/> $\\left( 9 + \\dfrac{39}{2} \\right) : 75\\% = 38$ (m) <br\/> (38 + 10) m\u00e9t v\u1ea3i \u1ee9ng v\u1edbi $100\\% - 20\\% = 80\\%$ s\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t <br\/> S\u1ed1 v\u1ea3i c\u00f2n l\u1ea1i sau ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0: <br\/> $(38 + 10) : 80\\% = 60$ (m) <br\/> (60 + 5) m\u00e9t v\u1ea3i \u1ee9ng v\u1edbi $1 - \\dfrac{1}{6} = \\dfrac{5}{6}$ t\u1ea5m v\u1ea3i c\u1ee7a c\u1eeda h\u00e0ng <br\/>T\u1ea5m v\u1ea3i d\u00e0i l\u00e0: <br\/> $(60 + 5) : \\dfrac{5}{6} = 78$ (m) <br\/> \u0110\u00e1p s\u1ed1: 78 m\u00e9t <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 78 <\/span> "}]}],"id_ques":1855},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["1508000"],["1 508 000"]]],"list":[{"point":10,"width":100,"type_input":"","ques":"M\u1ed9t m\u1ea3nh \u0111\u1ea5t \u0111\u01b0\u1ee3c chia l\u00e0m hai ph\u1ea7n, bi\u1ebft r\u1eb1ng $\\dfrac{3}{7}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t b\u1eb1ng $\\dfrac{2}{5}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai v\u00e0 $\\dfrac{9}{13}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai l\u1edbn h\u01a1n $\\dfrac{11}{20}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t l\u00e0 139600$m^2$. T\u00ednh di\u1ec7n t\u00edch c\u1ee7a m\u1ea3nh \u0111\u1ea5t. <br\/> \u0110\u00e1p s\u1ed1: _input_ $m^2$","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> Ph\u00e2n t\u00edch: <\/b> B\u00e0i cho $\\dfrac{3}{7}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t b\u1eb1ng $\\dfrac{2}{5}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai, ta t\u00ecm c\u00e1ch t\u00ednh t\u1ec9 s\u1ed1 gi\u1eefa di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai so v\u1edbi di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t. T\u1eeb \u0111\u00f3 ta t\u00ednh \u0111\u01b0\u1ee3c $\\dfrac{9}{13}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai so v\u1edbi di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t v\u00e0 t\u00ednh \u0111\u01b0\u1ee3c ph\u00e2n s\u1ed1 ch\u1ec9 $139600m^2$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t <br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh t\u1ec9 s\u1ed1 gi\u1eefa di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai so v\u1edbi di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t <br\/> Quy \u0111\u1ed3ng hai ph\u00e2n s\u1ed1 tr\u00ean r\u1ed3i th\u1ef1c hi\u1ec7n ph\u00e9p chia \u0111\u1ec3 t\u00ecm t\u1ec9 s\u1ed1 <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh t\u1ec9 s\u1ed1 gi\u1eefa $\\dfrac{9}{13}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai so v\u1edbi di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ecm ph\u1ea7n s\u1ed1 ch\u1ec9 $\\dfrac{9}{13}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai h\u01a1n $\\dfrac{11}{20}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t, \u1ee9ng v\u1edbi $139600m^2$ <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t c\u1ee7a m\u1ea3nh \u0111\u1ea5t <br\/> <b> B\u01b0\u1edbc 5: <\/b> T\u00ednh di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai c\u1ee7a m\u1ea3nh \u0111\u1ea5t <br\/> <b> B\u01b0\u1edbc 6: <\/b> T\u00ednh di\u1ec7n t\u00edch c\u1ee7a m\u1ea3nh \u0111\u1ea5t <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> V\u00ec $\\dfrac{3}{7}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t b\u1eb1ng $\\dfrac{2}{5}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai <br\/> Hay $\\dfrac{15}{35}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t b\u1eb1ng $\\dfrac{14}{35}$ ph\u1ea7n th\u1ee9 hai <br\/> T\u1ec9 s\u1ed1 gi\u1eefa di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai so v\u1edbi di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t l\u00e0: <br\/> $\\dfrac{15}{35} : \\dfrac{14}{35} = \\dfrac{15}{14}$ <br\/> C\u00f2n $\\dfrac{9}{13}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai b\u1eb1ng: <br\/> $\\dfrac{9}{13} . \\dfrac{15}{14} = \\dfrac{135}{182}$ di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t <br\/> Theo \u0111\u1ec1 b\u00e0i $139600m^2$ \u1ee9ng v\u1edbi $\\dfrac{135}{182} - \\dfrac{11}{20} = \\dfrac{349}{1820}$ (di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t) <br\/> Di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 nh\u1ea5t l\u00e0: <br\/> $139600 : \\dfrac{349}{1820} = 728000$ $(m^2)$ <br\/> Di\u1ec7n t\u00edch ph\u1ea7n th\u1ee9 hai l\u00e0: <br\/> $\\dfrac{15}{14} . 728000 = 780 000$ $(m^2)$ <br\/> Di\u1ec7n t\u00edch c\u1ee7a m\u1ea3nh \u0111\u1ea5t l\u00e0: <br\/> $728 000 + 780 000 = 1 508 000$ $(m^2)$ <br\/> \u0110\u00e1p s\u1ed1: 1 508 000 $m^2$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 1 508 000 <\/span> <br\/> <span class='basic_green'> <i> Nh\u1eadn x\u00e9t: C\u0103n c\u1ee9 v\u00e0o n\u1ed9i dung b\u00e0i to\u00e1n, kh\u00e9o l\u00e9o \u0111\u01b0a b\u00e0i to\u00e1n v\u1ec1 d\u1ea1ng t\u00ecm m\u1ed9t s\u1ed1 bi\u1ebft gi\u00e1 tr\u1ecb ph\u00e2n s\u1ed1 c\u1ee7a n\u00f3 <\/i> <\/span> "}]}],"id_ques":1856},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["36"]]],"list":[{"point":10,"width":50,"type_input":"","ques":"Trong m\u1ed9t l\u1edbp c\u1ee7a m\u1ed9t tr\u01b0\u1eddng ch\u1ec9 c\u00f3 hai lo\u1ea1i h\u1ecdc sinh gi\u1ecfi v\u00e0 kh\u00e1. Cu\u1ed1i h\u1ecdc k\u00ec I s\u1ed1 h\u1ecdc sinh gi\u1ecfi b\u1eb1ng $\\dfrac{2}{7}$ s\u1ed1 h\u1ecdc sinh kh\u00e1. \u0110\u1ebfn cu\u1ed1i n\u0103m c\u00f3 th\u00eam 1 h\u1ecdc sinh kh\u00e1 \u0111\u01b0\u1ee3c x\u1ebfp v\u00e0o lo\u1ea1i gi\u1ecfi n\u00ean s\u1ed1 h\u1ecdc sinh gi\u1ecfi b\u1eb1ng $\\dfrac{1}{3}$ s\u1ed1 h\u1ecdc sinh kh\u00e1. T\u00ednh s\u1ed1 h\u1ecdc sinh c\u1ee7a l\u1edbp. <br\/> \u0110\u00e1p s\u1ed1: _input_ h\u1ecdc sinh","hint":"Khi 1 h\u1ecdc sinh chuy\u1ec3n t\u1eeb lo\u1ea1i kh\u00e1 l\u00ean lo\u1ea1i gi\u1ecfi th\u00ec t\u1ed5ng s\u1ed1 h\u1ecdc sinh c\u1ee7a l\u1edbp kh\u00f4ng \u0111\u1ed5i","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> V\u1ebd s\u01a1 \u0111\u1ed3 <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh t\u1ec9 s\u1ed1 gi\u1eefa s\u1ed1 h\u1ecdc sinh gi\u1ecfi k\u00ec I so v\u1edbi h\u1ecdc sinh c\u1ea3 l\u1edbp <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh t\u1ec9 s\u1ed1 gi\u1eefa h\u1ecdc sinh gi\u1ecfi cu\u1ed1i n\u0103m so v\u1edbi h\u1ecdc sinh c\u1ea3 l\u1edbp <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ecm ph\u00e2n s\u1ed1 ch\u1ec9 1 h\u1ecdc sinh \u0111\u01b0\u1ee3c chuy\u1ec3n t\u1eeb lo\u1ea1i kh\u00e1 l\u00ean lo\u1ea1i gi\u1ecfi <br\/> <b> B\u01b0\u1edbc 5: <\/b> T\u00ednh s\u1ed1 h\u1ecdc sinh c\u1ee7a l\u1edbp \u0111\u00f3 <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Theo \u0111\u1ec1 b\u00e0i ta c\u00f3 s\u01a1 \u0111\u1ed3: <br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/daiso/bai36/lv3/img\/D638_K102.png' \/><\/center> <br\/> S\u1ed1 h\u1ecdc sinh gi\u1ecfi k\u00ec I so v\u1edbi s\u1ed1 h\u1ecdc sinh c\u1ea3 l\u1edbp l\u00e0: $\\dfrac{2}{7 + 2} = \\dfrac{2}{9}$ <br\/> S\u1ed1 h\u1ecdc sinh gi\u1ecfi cu\u1ed1i n\u0103m so v\u1edbi s\u1ed1 h\u1ecdc sinh c\u1ea3 l\u1edbp l\u00e0: $\\dfrac{1}{1 + 3} = \\dfrac{1}{4}$ <br\/> V\u00ec khi 1 h\u1ecdc sinh kh\u00e1 \u0111\u1ea1t lo\u1ea1i gi\u1ecfi th\u00ec s\u1ed1 h\u1ecdc sinh c\u1ee7a l\u1edbp kh\u00f4ng \u0111\u1ed5i <br\/> N\u00ean 1 h\u1ecdc sinh gi\u1ecfi \u1ee9ng v\u1edbi $\\dfrac{1}{4} - \\dfrac{2}{9} = \\dfrac{1}{36}$ h\u1ecdc sinh c\u1ea3 l\u1edbp <br\/> S\u1ed1 h\u1ecdc sinh c\u1ea3 l\u1edbp l\u00e0: <br\/> $1 : \\dfrac{1}{36} = 36$ (h\u1ecdc sinh) <br\/> \u0110\u00e1p s\u1ed1: 36 h\u1ecdc sinh <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 36 <\/span>"}]}],"id_ques":1857},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["10"],["4"]]],"list":[{"point":10,"width":50,"type_input":"","ques":" M\u1ed9t c\u00f4ng vi\u1ec7c \u0111\u01b0\u1ee3c giao cho m\u1ed9t th\u1ee3 b\u1eadc 1 l\u00e0m trong m\u1ed9t th\u1eddi gian r\u1ed3i giao cho m\u1ed9t th\u1ee3 b\u1eadc 2 l\u00e0m ti\u1ebfp cho xong. T\u00ednh xem m\u1ed7i ng\u01b0\u1eddi l\u00e0m vi\u1ec7c trong bao l\u00e2u, bi\u1ebft r\u1eb1ng t\u1ed5ng c\u1ed9ng c\u1ea3 hai ng\u01b0\u1eddi l\u00e0m vi\u1ec7c trong 14 gi\u1edd v\u00e0 \u0111\u1ec3 ho\u00e0n th\u00e0nh c\u00f4ng vi\u1ec7c \u0111\u00f3 m\u1ed9t m\u00ecnh, ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 c\u1ea7n 15 gi\u1edd, ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 c\u1ea7n 12 gi\u1edd. <br\/> \u0110\u00e1p s\u1ed1: Ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 l\u00e0m: _input_ gi\u1edd <br\/> Ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m: _input_ gi\u1edd","hint":"S\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p gi\u1ea3 thi\u1ebft t\u1ea1m","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n c\u00f4ng vi\u1ec7c m\u1ed7i ng\u01b0\u1eddi l\u00e0m \u0111\u01b0\u1ee3c trong 1 gi\u1edd <br\/> <b> B\u01b0\u1edbc 2: <\/b> Gi\u1ea3 thi\u1ebft r\u1eb1ng ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m c\u1ea3 14 gi\u1edd th\u00ec ng\u01b0\u1eddi \u0111\u00f3 l\u00e0m \u0111\u01b0\u1ee3c bao nhi\u00eau ph\u1ea7n c\u00f4ng vi\u1ec7c <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh s\u1ed1 ph\u1ea7n c\u00f4ng vi\u1ec7c d\u00f4i ra <br\/> <b> B\u01b0\u1edbc 4: <\/b> Trong 1 gi\u1edd ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m h\u01a1n ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 bao nhi\u00eau ph\u1ea7n c\u00f4ng vi\u1ec7c <br\/> <b> B\u01b0\u1edbc 5: <\/b> T\u00ednh th\u1eddi gian ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 \u0111\u00e3 l\u00e0m <br\/> L\u1ea5y s\u1ed1 ph\u1ea7n c\u00f4ng vi\u1ec7c d\u00f4i ra chia s\u1ed1 ph\u1ea7n c\u00f4ng vi\u1ec7c ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m h\u01a1n ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 <br\/> <b> B\u01b0\u1edbc 6: <\/b> T\u00ednh th\u1eddi gian ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 \u0111\u00e3 l\u00e0m <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Trong 1 gi\u1edd ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 l\u00e0m \u0111\u01b0\u1ee3c: $\\dfrac{1}{15}$ c\u00f4ng vi\u1ec7c, ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m \u0111\u01b0\u1ee3c $\\dfrac{1}{12}$ c\u00f4ng vi\u1ec7c <br\/> Gi\u1ea3 thi\u1ebft r\u1eb1ng ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m c\u1ea3 14 gi\u1edd th\u00ec ng\u01b0\u1eddi \u0111\u00f3 l\u00e0m \u0111\u01b0\u1ee3c: <br\/> $\\dfrac{1}{12} . 14 = \\dfrac{14}{12} = 1\\dfrac{1}{6}$ (c\u00f4ng vi\u1ec7c) <br\/> S\u1ed1 c\u00f4ng vi\u1ec7c d\u00f4i ra l\u00e0: $1\\dfrac{1}{6} - 1 = \\dfrac{1}{6}$ (c\u00f4ng vi\u1ec7c) <br\/> S\u1edf d\u0129 s\u1ed1 c\u00f4ng vi\u1ec7c d\u00f4i ra v\u00ec ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 \u0111\u00e3 l\u00e0m thay ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 <br\/> Trong 1 gi\u1edd ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m nhanh h\u01a1n ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 l\u00e0: <br\/> $\\dfrac{1}{12} - \\dfrac{1}{15} = \\dfrac{1}{60}$ (c\u00f4ng vi\u1ec7c) <br\/> Th\u1eddi gian ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 \u0111\u00e3 l\u00e0m l\u00e0: <br\/> $\\dfrac{1}{6} : \\dfrac{1}{60} = 10$ (gi\u1edd) <br\/> Th\u1eddi gian ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 \u0111\u00e3 l\u00e0m l\u00e0: <br\/> 14 - 10 = 4 (gi\u1edd) <br\/> \u0110\u00e1p s\u1ed1: Ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 l\u00e0m: 10 gi\u1edd <br\/> Ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2 l\u00e0m: 4 gi\u1edd <br\/> <span class='basic_pink'> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 10; 4 <\/span> <br\/> <span class='basic_green'> <i> Nh\u1eadn x\u00e9t: Trong ph\u01b0\u01a1ng ph\u00e1p gi\u1ea3 thi\u1ebft t\u1ea1m ng\u01b0\u1eddi ta \u0111\u01b0a ra c\u00e1c gi\u1ea3 \u0111\u1ecbnh m\u1edbi \u0111\u1ec3 \u0111\u01b0a b\u00e0i to\u00e1n v\u1ec1 c\u00e1c b\u00e0i to\u00e1n \u0111\u00e3 bi\u1ebft c\u00e1ch gi\u1ea3i. Gi\u1ea3 \u0111\u1ecbnh c\u1ee7a b\u00e0i to\u00e1n tr\u00ean l\u00e0m cho ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 c\u00f3 n\u0103ng su\u1ea5t nh\u01b0 ng\u01b0\u1eddi th\u1ee3 b\u1eadc 2, t\u1eeb \u0111\u00f3 t\u00ecm \u0111\u01b0\u1ee3c s\u1ef1 ch\u00eanh l\u1ec7ch v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng c\u00f4ng vi\u1ec7c c\u1ee7a to\u00e0n b\u1ed9 c\u00f4ng vi\u1ec7c, l\u1ea1i bi\u1ebft s\u1ef1 ch\u00eanh l\u1ec7ch c\u00f4ng vi\u1ec7c trong 1 gi\u1edd, t\u1eeb \u0111\u00f3 t\u00ecm \u0111\u01b0\u1ee3c s\u1ed1 gi\u1edd l\u00e0m vi\u1ec7c c\u1ee7a ng\u01b0\u1eddi th\u1ee3 b\u1eadc 1 <\/i> <\/span>"}]}],"id_ques":1858},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["5"]]],"list":[{"point":10,"width":50,"type_input":"","ques":" Ba th\u00fang cam c\u00f3 200 qu\u1ea3. Ng\u01b0\u1eddi ta l\u1ea5y $\\dfrac{1}{3}$ s\u1ed1 cam c\u1ee7a th\u00fang th\u1ee9 nh\u1ea5t, $\\dfrac{2}{5}$ s\u1ed1 cam c\u1ee7a th\u00fang th\u1ee9 hai v\u00e0 $\\dfrac{13}{15}$ s\u1ed1 cam c\u1ee7a th\u00fang th\u1ee9 3 th\u00ec \u0111\u01b0\u1ee3c 70 qu\u1ea3. H\u1ecfi n\u1ebfu l\u1ea5y $\\dfrac{1}{10}$ s\u1ed1 cam c\u1ee7a th\u00fang th\u1ee9 hai v\u00e0 $\\dfrac{4}{5}$ s\u1ed1 cam c\u1ee7a th\u00fang th\u1ee9 ba th\u00ec \u0111\u01b0\u1ee3c bao nhi\u00eau qu\u1ea3. <br\/> \u0110\u00e1p s\u1ed1: _input_ qu\u1ea3 ","hint":"","explain":"<span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> N\u1ebfu l\u1ea5y g\u1ea5p 3 l\u1ea7n s\u1ed1 cam \u0111\u00e3 l\u1ea5y \u1edf m\u1ed7i th\u00fang th\u00ec \u0111\u01b0\u1ee3c: <br\/> 70 . 3 = 210 (qu\u1ea3) <br\/> 210 qu\u1ea3 g\u1ed3m $3 . \\dfrac{1}{3} = 1$ th\u00fang th\u1ee9 nh\u1ea5t; $3 .\\dfrac{2}{5} = \\dfrac{6}{5}$ th\u00fang th\u1ee9 2; $3 . \\dfrac{13}{15} = \\dfrac{13}{5}$ th\u00fang th\u1ee9 3 <br\/> Nh\u01b0 v\u1eady n\u1ebfu l\u1ea5y g\u1ea5p 3 l\u1ea7n th\u00ec thi\u1ebfu 210 - 200 = 10 qu\u1ea3 <br\/> Hay 10 qu\u1ea3 g\u1ed3m $\\dfrac{6}{5} - 1 = \\dfrac{1}{5}$ th\u00fang th\u1ee9 2 v\u00e0 $\\dfrac{13}{5} - 1 = \\dfrac{8}{5}$ th\u00fang th\u1ee9 3. <br\/> V\u1eady n\u1ebfu l\u1ea5y $\\dfrac{1}{10}$ th\u00fang th\u1ee9 hai v\u00e0 $\\dfrac{4}{5}$ th\u00fang th\u1ee9 3 th\u00ec \u0111\u01b0\u1ee3c: <br\/> 10 : 2 = 5 (qu\u1ea3) <br\/> \u0110\u00e1p s\u1ed1: 5 qu\u1ea3 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 5 <\/span> "}]}],"id_ques":1859},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-1"],["2"]]],"list":[{"point":10,"width":50,"ques":"Cho $\\dfrac{2a - 3b}{4a + 5b} = \\dfrac{-4}{3}$. T\u00ednh t\u1ec9 s\u1ed1 $\\dfrac{a}{b}$? <br\/><br\/> \u0110\u00e1p \u00e1n l\u00e0 $\\dfrac{a}{b}$ = <div class=\"frac123\"><div class=\"ts\">_input_<\/div><div class=\"ms\">_input_<\/div><\/div>","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Chia c\u1ea3 t\u1eed v\u00e0 m\u1eabu c\u1ee7a ph\u00e2n s\u1ed1 $\\dfrac{2a - 3b}{4a + 5b}$ cho a l\u00e0m xu\u1ea5t hi\u1ec7n t\u1ec9 s\u1ed1 $\\dfrac{a}{b}$ <br\/> <b> B\u01b0\u1edbc 2: <\/b> Bi\u1ebfn \u0111\u1ed5i bi\u1ec3u th\u1ee9c tr\u00ean v\u00e0 t\u00ecm $\\dfrac{a}{b}$ <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Gi\u1ea3 s\u1eed $b \\neq 0$ ta c\u00f3: <br\/> $ \\dfrac{2a - 3b}{4a + 5b} = \\dfrac{-4}{3} \\\\ \\Rightarrow \\dfrac{\\dfrac{2a - 3b}{b}}{\\dfrac{4a + 5b}{b}} = \\dfrac{-4}{3} \\\\ \\Rightarrow \\dfrac{2 . \\dfrac{a}{b} - 3}{4 . \\dfrac{a}{b} + 5} = \\dfrac{-4}{3} \\\\ \\Rightarrow \\left( 2 . \\dfrac{a}{b} - 3 \\right) . 3 = (-4) . \\left( 4 . \\dfrac{a}{b} + 5 \\right) \\\\ 6 . \\dfrac{a}{b} - 9 = -16 . \\dfrac{a}{b} - 20 \\\\ 6 . \\dfrac{a}{b} + 16 . \\dfrac{a}{b} = -20 + 9 \\\\ 22 . \\dfrac{a}{b} = -11 \\\\ \\dfrac{a}{b} = \\dfrac{-1}{2}$"}]}],"id_ques":1860}],"lesson":{"save":0,"level":3}}