{"common":{"save":0,"post_id":"800","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"1541","post_id":"800","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" Cho 3 ph\u00e2n s\u1ed1 $\\dfrac{-5^2 - 5 . 3^2}{5^3 + 5^2 . 3^2}; \\dfrac{4^6 . 9^5 + 6^9 . 120}{8^4 . 3^{12} - 6^{11}}; \\dfrac{2929 - 101}{2 . 1919 + 404}$ <br\/> Sau khi r\u00fat g\u1ecdn v\u00e0 quy \u0111\u1ed3ng ta \u0111\u01b0\u1ee3c 3 ph\u00e2n s\u1ed1 n\u00e0o?","select":["A. $\\dfrac{-1}{15}; \\dfrac{4}{15}; \\dfrac{2}{15}$","B. $\\dfrac{-1}{15}; \\dfrac{12}{15}; \\dfrac{10}{15}$","C. $\\dfrac{-3}{15}; \\dfrac{12}{15}; \\dfrac{10}{15}$","D. $\\dfrac{-1}{15}; \\dfrac{4}{15}; \\dfrac{10}{15}$ "],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> R\u00fat g\u1ecdn c\u00e1c ph\u00e2n s\u1ed1 tr\u00ean <br\/> V\u1edbi ph\u00e2n s\u1ed1: $\\dfrac{4^6 . 9^5 + 6^9 . 120}{8^4 . 3^{12} - 6^{11}}$ \u0111\u01b0a c\u00e1c th\u1eeba s\u1ed1 v\u1ec1 c\u01a1 s\u1ed1 2 v\u00e0 c\u01a1 s\u1ed1 3 r\u1ed3i r\u00fat g\u1ecdn <br\/> V\u1edbi ph\u00e2n s\u1ed1 $\\dfrac{2929 - 101}{2 . 1919 + 404}$ nh\u00f3m 101 ra ngo\u00e0i r\u1ed3i r\u00fat g\u1ecdn <br\/> <b> B\u01b0\u1edbc 2: <\/b> Quy \u0111\u1ed3ng 3 ph\u00e2n s\u1ed1 sau khi r\u00fat g\u1ecdn <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> $\\dfrac{-5^2 - 5 . 3^2}{5^3 + 5^2 . 3^2} = \\dfrac{-5 . (5 + 3^2)}{5^2 . (5 + 3^2)} = \\dfrac{-1}{5}$ <br\/><br\/> $\\begin{align*}& \\dfrac{4^6 . 9^5 + 6^9 . 120}{8^4 . 3^{12} - 6^{11}} \\\\\\\\ &= \\dfrac{(2^2)^6 . (3^2)^5 + (2 . 3)^9 . 2^3 . 3 . 5}{(2^3)^4 . 3^{12} - (2 . 3)^{11}} \\\\\\\\ &= \\dfrac{2^{12} . 3^{10} + 2^9 . 3^9 . 2^3 . 3 . 5}{2^{12} . 3^{12} - 2^{11} . 3^{11}} \\\\\\\\ &= \\dfrac{2^{12} . 3^{10} + 2^{12} . 3^{10} . 5}{2^{11} . (2 . 3^{12} - 1)} \\\\\\\\ &= \\dfrac{2^{12} . 3^{10} . (1 + 5)}{2^{11} . 3^{11} . (2 . 3 - 1)} \\\\\\\\ &= \\dfrac{2 . 6}{3 . 5} = \\dfrac{4}{5} \\end{align*}$ <br\/> $\\begin{align*}& \\dfrac{2929 - 101}{2 . 1919 + 404} = \\dfrac{101 . (29 - 1)}{2 . 19 . 101 + 4 . 101} = \\dfrac{101 . 28}{101 . (38 + 4)} = \\dfrac{2}{3} \\end{align*}$ <br\/> Quy \u0111\u1ed3ng m\u1eabu s\u1ed1 c\u00e1c ph\u00e2n s\u1ed1 tr\u00ean ta \u0111\u01b0\u1ee3c: <br\/> $\\dfrac{-1}{5} = \\dfrac{-1 . 3}{5 . 3} = \\dfrac{-3}{15}$ <br\/> $\\dfrac{4}{5} = \\dfrac{4 . 3}{5 . 3} = \\dfrac{12}{15}$ <br\/> $\\dfrac{2}{3} = \\dfrac{2 . 5}{3 . 5} = \\dfrac{10}{15}$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C. $\\dfrac{-3}{15}; \\dfrac{12}{15}; \\dfrac{10}{15}$ <\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:52"},{"id":"1542","post_id":"800","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" Cho 2 ph\u00e2n s\u1ed1 $\\dfrac{2^5 . 7 + 2^5}{2^5 . 5^2 - 2^5 . 3}; \\dfrac{3^4 . 5 - 3^6}{3^4 . 13 + 3^4}$ <br\/> Sau khi r\u00fat g\u1ecdn v\u00e0 quy \u0111\u1ed3ng ta \u0111\u01b0\u1ee3c 2 ph\u00e2n s\u1ed1 n\u00e0o?","select":["A. $\\dfrac{4}{77}; \\dfrac{-2}{77}$","B. $\\dfrac{28}{77}; \\dfrac{-2}{77}$","C. $\\dfrac{28}{77}; \\dfrac{-22}{77}$","D. $\\dfrac{4}{77}; \\dfrac{-22}{77}$ "],"hint":"","explain":"<span class='basic_left'> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> $\\begin{align*}& \\dfrac{2^5 . 7 + 2^5}{2^5 . 5^2 - 2^5 . 3} \\\\ &= \\dfrac{2^5 . (7 + 1)}{2^5 . (5^2 - 3)} \\\\ & = \\dfrac{8}{25 - 3} \\\\ &= \\dfrac{8}{22} \\\\ &= \\dfrac{4}{11} \\end{align*}$ <br\/> $\\begin{align*}& \\dfrac{3^4 . 5 - 3^6}{3^4 . 13 + 3^4} \\\\ &= \\dfrac{3^4 . (5 - 3^2)}{3^4 . (13 + 1)} \\\\ &= \\dfrac{5 - 9}{14} \\\\ &= \\dfrac{-2}{7} \\end{align*}$ <br\/> Quy \u0111\u1ed3ng hai ph\u00e2n s\u1ed1 tr\u00ean ta \u0111\u01b0\u1ee3c: <br\/> $\\dfrac{-2}{7} = \\dfrac{-2 . 11}{7 . 11} = \\dfrac{-22}{77}$ <br\/> $\\dfrac{4}{11} = \\dfrac{4 . 7}{11 . 7} = \\dfrac{28}{77}$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C. $\\dfrac{28}{77}; \\dfrac{-22}{77}$ <\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:52"},{"id":"1543","post_id":"800","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["<"]]],"list":[{"point":10,"width":50,"type_input":"","ques":"H\u00e3y \u0111i\u1ec1n d\u1ea5u (>, < ho\u1eb7c =) th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng <br\/> $\\dfrac{2003 . 2004 - 1}{2003 . 2004}$ _input_ $\\dfrac{2004 . 2005 - 1}{2004 . 2005}$","hint":"S\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p so s\u00e1nh ph\u1ea7n b\u00f9","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Ph\u00e2n t\u00edch hai ph\u00e2n s\u1ed1 tr\u00ean th\u00e0nh $1 - \\dfrac{a}{b}$ v\u00e0 $1 - \\dfrac{c}{d}$ <br\/> <b> B\u01b0\u1edbc 2: <\/b> So s\u00e1nh $\\dfrac{a}{b}$ v\u00e0 $\\dfrac{c}{d}$ <br\/> <b> B\u01b0\u1edbc 3: <\/b> So s\u00e1nh $1 - \\dfrac{a}{b}$ v\u00e0 $1 - \\dfrac{c}{d}$ <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $\\dfrac{2003 . 2004 - 1}{2003 . 2004} = \\dfrac{2003 . 20004}{2003. 2004} - \\dfrac{1}{2003 . 2004} = 1 - \\dfrac{1}{2003 . 2004}$ <br\/> $\\dfrac{2004 . 2005 - 1}{2004 . 2005} = \\dfrac{2004 . 2005}{2004 . 2005} - \\dfrac{1}{2004 . 2005} = 1 - \\dfrac{1}{2004 . 2005}$ <br\/> V\u00ec $\\dfrac{1}{2003 . 2004} > \\dfrac{1}{2004 . 2005}$ <br\/> N\u00ean $1 - \\dfrac{1}{2004 . 2005} > 1 - \\dfrac{1}{2003 . 2004}$ <br\/> Hay $\\dfrac{2003 . 2004 - 1}{2003 . 2004} < \\dfrac{2004 . 2005 - 1}{2004 . 2005}$ <br\/> <span class='basic_pink'> V\u1eady ph\u00e2n d\u1ea5u c\u1ea7n \u0111i\u1ec1n l\u00e0: < <\/span> "}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:52"}]}