Quy tắc dấu ngoặc - Bài tập trung bình số 2

Home Lớp 6 Toán lớp 6 - Sách kết nối tri thức Bài 15: Quy tắc dấu ngoặcBài tập trung bình

{"common":{"save":0,"post_id":"4794","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8154","post_id":"4794","mon_id":"1158113","chapter_id":"1158128","question":"Tính m\u1ed9t cách h\u1ee3p lí<\/p>222 - (151 + 212 - 171)<\/p>","options":["-30","30","300"],"correct":"2","level":"2","hint":"Khi b\u1ecf ngo\u1eb7c ta ph\u1ea3i gi\u1eef nguyên d\u1ea5u<\/strong> các s\u1ed1 trong ngo\u1eb7c n\u1ebfu tr\u01b0\u1edbc ngo\u1eb7c là d\u1ea5u c\u1ed9ng<\/strong> và \u0111\u1ed5i d\u1ea5u<\/strong> các s\u1ed1 trong ngo\u1eb7c n\u1ebfu tr\u01b0\u1edbc ngo\u1eb7c là d\u1ea5u tr\u1eeb.<\/strong><\/p>Chú ý. Khi thay \u0111\u1ed5i v\u1ecb trí c\u1ee7a các s\u1ed1 h\u1ea1ng ph\u1ea3i gi\u1eef nguyên d\u1ea5u c\u1ee7a chúng. Khi \u0111\u01b0a các s\u1ed1 vào ngo\u1eb7c mà tr\u01b0\u1edbc ngo\u1eb7c có d\u1ea5u tr\u1eeb ta ph\u1ea3i \u0111\u1ed5i d\u1ea5u các s\u1ed1 \u0111ó.<\/p>","answer":"   222 - (151 + 212 - 171)<\/p>= 222 - 151 - 212 + 171<\/p>= (222 - 212) + (171 - 151)<\/p>= 10 + 20<\/p>= 30<\/p>V\u1eady \u0111áp án \u0111úng là 30<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"132","test":"1","date":"2021-10-03 12:20:53","option_type":"number","len":0},{"id":"8155","post_id":"4794","mon_id":"1158113","chapter_id":"1158128","question":"Tính m\u1ed9t cách h\u1ee3p lí<\/p>M = 256 + 57 - 258 - 59 + 160 - 162 + 100<\/p>\u0110áp s\u1ed1: M = <input class=\"tim_x input_number\" tpl=\"dien_so\" type=\"text\"\/><\/strong><\/p>","options":"","correct":["[\"94\"]"],"level":"2","hint":"Khi b\u1ecf ngo\u1eb7c ta ph\u1ea3i gi\u1eef nguyên d\u1ea5u<\/strong> các s\u1ed1 trong ngo\u1eb7c n\u1ebfu tr\u01b0\u1edbc ngo\u1eb7c là d\u1ea5u c\u1ed9ng<\/strong> và \u0111\u1ed5i d\u1ea5u<\/strong> các s\u1ed1 trong ngo\u1eb7c n\u1ebfu tr\u01b0\u1edbc ngo\u1eb7c là d\u1ea5u tr\u1eeb.<\/strong><\/p>Chú ý. Khi thay \u0111\u1ed5i v\u1ecb trí c\u1ee7a các s\u1ed1 h\u1ea1ng ph\u1ea3i gi\u1eef nguyên d\u1ea5u c\u1ee7a chúng. Khi \u0111\u01b0a các s\u1ed1 vào ngo\u1eb7c mà tr\u01b0\u1edbc ngo\u1eb7c có d\u1ea5u tr\u1eeb ta ph\u1ea3i \u0111\u1ed5i d\u1ea5u các s\u1ed1 \u0111ó.<\/p>","answer":"M = 256 + 57 - 258 - 59 + 160 - 162 + 100<\/p>M = (256 - 258) + (57 - 59) + (160 - 162) + 100<\/p>M = -2 - 2 - 2 + 100<\/p>M = 94<\/p>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n là 94<\/strong><\/span>.<\/p>","type":"blank","extra_type":"","time":"0","user_id":"132","test":"1","date":"2021-10-03 12:24:56"},{"id":"8157","post_id":"4794","mon_id":"1158113","chapter_id":"1158128","question":"Tính m\u1ed9t cách h\u1ee3p lí:<\/p>N = 130 + 16 - 160 - 270 - 46 + 240<\/p>","options":["N = 90","N = -90","N = -60"],"correct":"2","level":"2","hint":"Khi b\u1ecf ngo\u1eb7c ta ph\u1ea3i gi\u1eef nguyên d\u1ea5u<\/strong> các s\u1ed1 trong ngo\u1eb7c n\u1ebfu tr\u01b0\u1edbc ngo\u1eb7c là d\u1ea5u c\u1ed9ng<\/strong> và \u0111\u1ed5i d\u1ea5u<\/strong> các s\u1ed1 trong ngo\u1eb7c n\u1ebfu tr\u01b0\u1edbc ngo\u1eb7c là d\u1ea5u tr\u1eeb.<\/strong><\/p>Chú ý. Khi thay \u0111\u1ed5i v\u1ecb trí c\u1ee7a các s\u1ed1 h\u1ea1ng ph\u1ea3i gi\u1eef nguyên d\u1ea5u c\u1ee7a chúng. Khi \u0111\u01b0a các s\u1ed1 vào ngo\u1eb7c mà tr\u01b0\u1edbc ngo\u1eb7c có d\u1ea5u tr\u1eeb ta ph\u1ea3i \u0111\u1ed5i d\u1ea5u các s\u1ed1 \u0111ó.<\/p>","answer":"N = 130 + 16 - 160 - 270 - 46 + 240<\/p>N = (130 - 160) + (16 - 46) + (240 - 270)<\/p>N = - 30 - 30 - 30<\/p>N = -90<\/p>V\u1eady \u0111áp án \u0111úng là N = -90<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"132","test":"1","date":"2021-10-03 12:29:58","option_type":"txt","len":0}]}