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Home Lớp 6 Toán lớp 6 - Sách kết nối tri thức Ước và bộiBài tập nâng cao

{"common":{"save":0,"post_id":"739","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"601","post_id":"739","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["19"],["7"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":" <center><img src='img\/9.jpg' \/><\/center> <br\/> T\u00ecm s\u1ed1 chia v\u00e0 th\u01b0\u01a1ng c\u1ee7a m\u1ed9t ph\u00e9p chia c\u00f3 s\u1ed1 b\u1ecb chia b\u1eb1ng 145, s\u1ed1 d\u01b0 l\u00e0 12. Bi\u1ebft th\u01b0\u01a1ng l\u00e0 s\u1ed1 t\u1ef1 nhi\u00ean kh\u00e1c 1 <br\/> V\u1eady s\u1ed1 chia l\u00e0: _input_ <br\/> Th\u01b0\u01a1ng l\u00e0: _input_ ","hint":"S\u1ed1 b\u1ecb chia = th\u01b0\u01a1ng . s\u1ed1 chia + s\u1ed1 d\u01b0 ","explain":"H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> G\u1ecdi x l\u00e0 s\u1ed1 chia, a l\u00e0 th\u01b0\u01a1ng <br\/> Theo b\u00e0i ra ta c\u00f3: 145 = a . x + 12 (1) <br\/> B\u01b0\u1edbc 2: <\/b>Bi\u1ebfn \u0111\u1ed5i (1) v\u00e0 d\u1ef1a v\u00e0o kh\u00e1i ni\u1ec7m b\u1ed9i, \u01b0\u1edbc \u0111\u1ec3 t\u00ecm a v\u00e0 x <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> G\u1ecdi x l\u00e0 s\u1ed1 chia, a l\u00e0 th\u01b0\u01a1ng ($a, x \\in \\mathbb{N}$) <br\/> Theo b\u00e0i ra ta c\u00f3: 145 = a . x + 12 (x > 12; a $\\neq$ 1) <br\/> $\\begin{align*} \\Rightarrow & a. x = 145 - 12 \\\\ & a . x = 133 \\end{align*}$ <br\/> V\u00ec a $\\neq$ 1 n\u00ean a, x ch\u00ednh l\u00e0 hai \u01b0\u1edbc kh\u00e1c 1 c\u1ee7a 133 <br\/> Ta c\u00f3: 133 = 19 . 7 <br\/> N\u1ebfu th\u01b0\u01a1ng l\u00e0 19 $\\Rightarrow$ S\u1ed1 chia l\u00e0 7 (kh\u00f4ng th\u1ecfa m\u00e3n v\u00ec d\u01b0 l\u00e0 12) <br\/> N\u1ebfu th\u01b0\u01a1ng l\u00e0 7 $\\Rightarrow$ S\u1ed1 chia l\u00e0 19 (th\u1ecfa m\u00e3n) <br\/> Ph\u00e9p chia \u0111\u00f3 l\u00e0: 145 : 19 = 7 d\u01b0 12 <br\/> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u1ea7n l\u01b0\u1ee3t l\u00e0: 19; 7 <\/span>"}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:43"},{"id":"602","post_id":"739","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"],["5"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":" <center><img src='img\/10.jpg' \/><\/center> <br\/> T\u00ecm c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean x, y bi\u1ebft: <br\/> $(2x + 1)(y - 3) = 10, (x > 1)$ <br\/> V\u1eady x = _input_; y = _input_ ","hint":"V\u00ec x, y l\u00e0 c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean n\u00ean (2x + 1) v\u00e0 (y - 3) l\u00e0 \u01b0\u1edbc c\u1ee7a 10","explain":"H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> Vi\u1ebft 10 th\u00e0nh t\u00edch c\u1ee7a 2 s\u1ed1 t\u1ef1 nhi\u00ean <br\/> B\u01b0\u1edbc 2: <\/b> Cho (2x + 1) v\u00e0 (y - 3) b\u1eb1ng c\u00e1c gi\u00e1 tr\u1ecb v\u1eeba vi\u1ebft \u1edf b\u01b0\u1edbc 1 t\u1eeb \u0111\u00f3 t\u00ecm x v\u00e0 y <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> Ta c\u00f3: 10 = 1 . 10 = 2 . 5 <br\/> V\u00ec x, y l\u00e0 c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean n\u00ean (2x + 1) v\u00e0 (y - 3) l\u00e0 c\u00e1c \u01b0\u1edbc c\u1ee7a 10 v\u00e0 (2x + 1) l\u00e0 s\u1ed1 l\u1ebb n\u00ean: <br\/> Ho\u1eb7c $\\begin{cases} 2x + 1 = 1 \\Rightarrow x = 0 \\\\y - 3 = 10 \\Rightarrow y = 13 \\end{cases}$ (lo\u1ea1i v\u00ec x > 1) <br\/> Ho\u1eb7c $\\begin{cases} 2x + 1 = 5 \\Rightarrow x = 2 \\\\ y - 3 = 2 \\Rightarrow y = 5 \\end{cases}$ (th\u1ecfa m\u00e3n) <br\/> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u1ea7n l\u01b0\u1ee3t l\u00e0: x = 2; y = 5 <\/span>"}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:43"},{"id":"603","post_id":"739","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2","5"],["12","0"],["5","2"],["0","12"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":" <center><img src='img\/10.jpg' \/><\/center> <br\/> T\u00ecm c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean x, y bi\u1ebft: <br\/> $(2x - 3)(y + 2) = 14, (x > 1)$ <br\/> V\u1eady x = _input_; y = _input_ ho\u1eb7c x = _input_; y = _input_ ","hint":"V\u00ec x, y l\u00e0 c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean n\u00ean (2x - 3) v\u00e0 (y + 2) l\u00e0 \u01b0\u1edbc c\u1ee7a 14","explain":"H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> Vi\u1ebft 14 th\u00e0nh t\u00edch c\u1ee7a 2 s\u1ed1 t\u1ef1 nhi\u00ean <br\/> B\u01b0\u1edbc 2: <\/b> Cho (2x - 3) v\u00e0 (y + 2) b\u1eb1ng c\u00e1c gi\u00e1 tr\u1ecb v\u1eeba vi\u1ebft \u1edf b\u01b0\u1edbc 1 t\u1eeb \u0111\u00f3 t\u00ecm x v\u00e0 y <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> Ta c\u00f3: 14 = 1 . 14 = 2 . 7 <br\/> V\u00ec x, y l\u00e0 c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean n\u00ean (2x - 3) v\u00e0 (y + 2) l\u00e0 c\u00e1c \u01b0\u1edbc c\u1ee7a 14 v\u00e0 (2x - 3) l\u00e0 s\u1ed1 l\u1ebb n\u00ean: <br\/> Ho\u1eb7c $\\begin{cases} 2x - 3 = 1 \\Rightarrow x = 2 \\\\y + 2 = 14 \\Rightarrow y = 12 \\end{cases}$ (th\u1ecfa m\u00e3n) <br\/> Ho\u1eb7c $\\begin{cases} 2x - 3 = 7 \\Rightarrow x = 5 \\\\ y + 2 = 2 \\Rightarrow y = 0 \\end{cases}$ (th\u1ecfa m\u00e3n) <br\/> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u1ea7n l\u01b0\u1ee3t l\u00e0: x = 2; y = 12 ho\u1eb7c x = 5, y = 0 <\/span>"}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:43"}]}