{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" <span class='basic_left'> Thu g\u1ecdn r\u1ed3i s\u1eafp x\u1ebfp \u0111a th\u1ee9c sau theo l\u0169y th\u1eeba gi\u1ea3m d\u1ea7n c\u1ee7a bi\u1ebfn: <br\/> $1-6{{x}^{7}}+5{{x}^{4}}-2+13{{x}^{5}}-8{{x}^{7}}$ <\/span>","select":["A. $-1+5x^4+13x^5-14x^7$","B. $-14{{x}^{7}}+13{{x}^{5}}+5{{x}^{4}}-1$","C. $-2{{x}^{7}}+13{{x}^{5}}+5{{x}^{4}}+1$","D. $2{{x}^{7}}+13{{x}^{5}}+5{{x}^{4}}-3$"],"hint":"","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{align} & 1-6{{x}^{7}}+5{{x}^{4}}-2+13{{x}^{5}}-8{{x}^{7}} \\\\ & =\\left( -6{{x}^{7}}-8{{x}^{7}} \\right)+13{{x}^{5}}+5{{x}^{4}}+\\left( 1-2 \\right) \\\\ & =-14{{x}^{7}}+13{{x}^{5}}+5{{x}^{4}}-1 \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span>","column":2}]}],"id_ques":1221},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["3"],["2"],["3"],["-8"]]],"list":[{"point":5,"width":30,"content":"","type_input":"","ques":" <span class='basic_left'>Thu g\u1ecdn r\u1ed3i s\u1eafp x\u1ebfp \u0111a th\u1ee9c sau theo l\u0169y th\u1eeba gi\u1ea3m d\u1ea7n c\u1ee7a bi\u1ebfn: <br\/> $A=4{{x}^{5}}+3x-2{{x}^{2}}-{{x}^{5}}+4{{x}^{2}}-8$ <br\/> <br\/> <b> \u0110\u00e1p \u00e1n:<\/b> $A=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}{{x}^{5}}+\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}{{x}^{2}}+\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}x+\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$<\/span> ","explain":"<span class='basic_left'>Ta c\u00f3: <br\/> $\\begin{align} & A=4{{x}^{5}}+3x-2{{x}^{2}}-{{x}^{5}}+4{{x}^{2}}-8 \\\\ & \\,\\,\\,\\,\\,\\,=\\left( 4{{x}^{5}}-{{x}^{5}} \\right)+\\left( -2{{x}^{2}}+4{{x}^{2}} \\right)+3x-8 \\\\ & \\,\\,\\,\\,\\,\\,=3{{x}^{5}}+2{{x}^{2}}+3x-8 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o c\u00e1c \u00f4 tr\u1ed1ng l\u1ea7n l\u01b0\u1ee3t l\u00e0 $3;2;3;-8$.<\/span><\/span>"}]}],"id_ques":1222},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y \u0110\u00fang hay Sai","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" B\u1eadc c\u1ee7a \u0111a th\u1ee9c $2y-3y^2+3y^2-2y$ l\u00e0 $2$","select":["\u0110\u00fang","Sai"],"explain":"<span class='basic_left'> Thu g\u1ecdn \u0111a th\u1ee9c: <br\/> $2y-3y^2+3y^2-2y=(-3y^2+3y^2)+(2y-2y)=0$ <br\/> $0$ l\u00e0 \u0111a th\u1ee9c kh\u00f4ng c\u00f3 b\u1eadc. <br\/> Kh\u1eb3ng \u0111\u1ecbnh c\u1ee7a \u0111\u1ec1 b\u00e0i l\u00e0 sai. <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 Sai.<\/span> <br\/> <b> Sai l\u1ea7m c\u1ea7n tr\u00e1nh:<\/b> <i> Tr\u01b0\u1edbc khi t\u00ecm b\u1eadc c\u1ee7a m\u1ed9t \u0111a th\u1ee9c, ta \u0111i thu g\u1ecdn \u0111a th\u1ee9c \u0111\u00f3 r\u1ed3i m\u1edbi t\u00ecm b\u1eadc c\u1ee7a n\u00f3. <\/i><\/span>","column":2}]}],"id_ques":1223},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" B\u1eadc c\u1ee7a \u0111a th\u1ee9c $3x^2-2x+7+2x-3x^2-6$ l\u00e0:","select":["A. $0$","B. $1$","C. $2$","D. Kh\u00f4ng c\u00f3 b\u1eadc"],"hint":"","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $3x^2-2x+7+2x-3x^2-6$ <br\/> $=(3x^2-3x^2)+(-2x+2x)+(7-6)$ <br\/> $=0+0+1=1$ <br\/> $1$ l\u00e0 \u0111a th\u1ee9c b\u1eadc kh\u00f4ng. <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":1224},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-1"],["7"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" Cho \u0111a th\u1ee9c: $B=-6{{x}^{3}}+5x-1+2{{x}^{2}}+6{{x}^{3}}-2x+5{{x}^{2}}$ <br\/> H\u1ec7 s\u1ed1 t\u1ef1 do c\u1ee7a \u0111a th\u1ee9c $B$ l\u00e0 _input_ <br\/> H\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c $B$ l\u00e0 _input_ ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Thu g\u1ecdn \u0111a th\u1ee9c $B$ r\u1ed3i t\u00ecm h\u1ec7 s\u1ed1 t\u1ef1 do v\u00e0 h\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a n\u00f3. <br\/> + H\u1ec7 s\u1ed1 t\u1ef1 do l\u00e0 h\u1ec7 s\u1ed1 c\u1ee7a l\u0169y th\u1eeba b\u1eadc $0$ c\u1ee7a bi\u1ebfn <br\/> + H\u1ec7 s\u1ed1 cao nh\u1ea5t l\u00e0 h\u1ec7 s\u1ed1 c\u1ee7a l\u0169y th\u1eeba cao nh\u1ea5t c\u1ee7a bi\u1ebfn<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/> $\\begin{align} & B=-6{{x}^{3}}+5x-1+2{{x}^{2}}+6{{x}^{3}}-2x+5{{x}^{2}} \\\\ & \\,\\,\\,\\,\\,=\\left( -6{{x}^{3}}+6{{x}^{3}} \\right)+\\left( 2{{x}^{2}}+5{{x}^{2}} \\right)+\\left( 5x-2x \\right)-1 \\\\ & \\,\\,\\,\\,=0+7{{x}^{2}}+3x-1 \\\\ & \\,\\,\\,\\,=7{{x}^{2}}+3x-1 \\\\ \\end{align}$ <br\/> H\u1ec7 s\u1ed1 t\u1ef1 do c\u1ee7a $B$ l\u00e0 $-1$ <br\/> L\u0169y th\u1eeba cao nh\u1ea5t c\u1ee7a bi\u1ebfn l\u00e0 $2$ n\u00ean h\u1ec7 s\u1ed1 $7$ c\u1ee7a l\u0169y th\u1eeba cao nh\u1ea5t l\u00e0 h\u1ec7 s\u1ed1 cao nh\u1ea5t. <br\/> <span class='basic_pink'> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o c\u00e1c \u00f4 tr\u1ed1ng l\u1ea7n l\u01b0\u1ee3t l\u00e0 $-1;7$.<\/span><\/span>"}]}],"id_ques":1225},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["4"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" <span class='basic_left'> X\u00e1c \u0111\u1ecbnh h\u1ec7 s\u1ed1 $a$ c\u1ee7a \u0111a th\u1ee9c $P(x)=ax+2$ bi\u1ebft r\u1eb1ng $P(-1)=-2$ <br\/> <b> \u0110\u00e1p \u00e1n:<\/b> $a=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$<\/span> ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> $P(-1)=-2$ t\u1ee9c l\u00e0 gi\u00e1 tr\u1ecb c\u1ee7a \u0111a th\u1ee9c $P$ t\u1ea1i $x=-1$ l\u00e0 $-2$ <br\/> Do \u0111\u00f3, thay $x=-1$ v\u00e0o \u0111a th\u1ee9c $P$ v\u00e0 cho gi\u00e1 tr\u1ecb c\u1ee7a \u0111a th\u1ee9c \u0111\u00f3 b\u1eb1ng $-2$ \u0111\u1ec3 t\u00ecm $a$ <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/> $\\begin{align} P\\left( -1 \\right)&=-2 \\\\ a\\,.\\left( -1 \\right)+2 &=-2 \\\\ -a+2 &=-2 \\\\ -a &=-4 \\\\ a &=4 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $4$.<\/span><\/span>"}]}],"id_ques":1226},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" <span class='basic_left'> Cho $P\\left( x \\right)=100{{x}^{100}}+99{{x}^{99}}+98{{x}^{98}}+\\cdots +2{{x}^{2}}+x$ <br\/> Ta t\u00ednh \u0111\u01b0\u1ee3c $P(1)$ b\u1eb1ng: <\/span>","select":["A. $4000$","B. $4950$","C. $5000$","D. $5050$"],"explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> Thay $x=1$ v\u00e0o \u0111a th\u1ee9c $P$ r\u1ed3i t\u00ednh. <br\/> C\u00f4ng th\u1ee9c t\u00ednh t\u1ed5ng $n$ s\u1ed1 t\u1ef1 nhi\u00ean li\u00ean ti\u1ebfp: $\\dfrac{(\\text{s\u1ed1 \u0111\u1ea7u +s\u1ed1 cu\u1ed1i}).n}{2}$ <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/> $\\begin{align} & P\\left( x \\right)=100{{x}^{100}}+99{{x}^{99}}+98{{x}^{98}}+\\cdots +2{{x}^{2}}+x \\\\ & \\Rightarrow P\\left( 1 \\right)={{100.1}^{100}}+{{99.1}^{99}}+{{98.1}^{98}}+\\cdots +{{2.1}^{2}}+1 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=100+99+98+\\cdots +2+1 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\dfrac{\\left( 100+1 \\right).100}{2} \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=101.50 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=5050 \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span>","column":4}]}],"id_ques":1227},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" <span class='basic_left'> Cho c\u00e1c \u0111a th\u1ee9c: <br\/> $A=3x-2{{x}^{2}}-2+6{{x}^{3}}$ <br\/> $ B=3{{x}^{2}}-x-2{{x}^{3}}+4 $ <br\/> $ C=1+4{{x}^{3}}-2x$ <br\/> T\u1ed5ng $A+B+C$ l\u00e0: <\/span>","select":["A. $12{{x}^{3}}-{{x}^{2}}+3$","B. $8{{x}^{3}}+{{x}^{2}}+6x+3$","C. $8{{x}^{3}}+{{x}^{2}}+3$","D. $12{{x}^{3}}-{{x}^{2}}+6x+3$"],"explain":"<span class='basic_left'>Ta c\u00f3: <br\/> $\\begin{align}& A+B+C=\\left( 3x-2{{x}^{2}}-2+6{{x}^{3}} \\right)+\\left( 3{{x}^{2}}-x-2{{x}^{3}}+4 \\right)+\\left( 1+4{{x}^{3}}-2x \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=3x-2{{x}^{2}}-2+6{{x}^{3}}+3{{x}^{2}}-x-2{{x}^{3}}+4+1+4{{x}^{3}}-2x \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\left( 6{{x}^{3}}-2{{x}^{3}}+4{{x}^{3}} \\right)+\\left( -2{{x}^{2}}+3{{x}^{2}} \\right)+\\left( 3x-x-2x \\right)+\\left( -2+4+1 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=8{{x}^{3}}+{{x}^{2}}+3 \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span>","column":2}]}],"id_ques":1228},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" <span class='basic_left'> Cho c\u00e1c \u0111a th\u1ee9c: <br\/> $A=3x-2{{x}^{2}}-2+6{{x}^{3}}$ <br\/> $ B=3{{x}^{2}}-x-2{{x}^{3}}+4 $ <br\/> $ C=1+4{{x}^{3}}-2x$ <br\/> Hi\u1ec7u $A-B-C$ l\u00e0: <\/span>","select":["A. $4{{x}^{3}}-5{{x}^{2}}+6x-7$","B. $8{{x}^{3}}+{{x}^{2}}+6x-7$","C. $4{{x}^{3}}+5{{x}^{2}}+6x+7$","D. $12{{x}^{3}}-5{{x}^{2}}+5x+3$"],"explain":"<span class='basic_left'>Ta c\u00f3: <br\/> $\\begin{align} & A-B-C=\\left( 3x-2{{x}^{2}}-2+6{{x}^{3}} \\right)-\\left( 3{{x}^{2}}-x-2{{x}^{3}}+4 \\right)-\\left( 1+4{{x}^{3}}-2x \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=3x-2{{x}^{2}}-2+6{{x}^{3}}-3{{x}^{2}}+x+2{{x}^{3}}-4-1-4{{x}^{3}}+2x \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\left( 6{{x}^{3}}+2{{x}^{3}}-4{{x}^{3}} \\right)+\\left( -2{{x}^{2}}-3{{x}^{2}} \\right)+\\left( 3x+x+2x \\right)+\\left( -2-4-1 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=4{{x}^{3}}-5{{x}^{2}}+6x-7 \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":1229},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-5"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" T\u00ecm $x,$ bi\u1ebft $ \\left( 5{{x}^{3}}-4{{x}^{2}}+2x-1 \\right)+\\left( 3-x+4{{x}^{2}}-5{{x}^{3}} \\right) =-3$ <br\/> <b> \u0110\u00e1p \u00e1n: <\/b> $x=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$","explain":"<span class='basic_left'>Ta c\u00f3: <br\/> $\\begin{align} \\left( 5{{x}^{3}}-4{{x}^{2}}+2x-1 \\right)+\\left( 3-x+4{{x}^{2}}-5{{x}^{3}} \\right) &=-3 \\\\ 5{{x}^{3}}-4{{x}^{2}}+2x-1+3-x+4{{x}^{2}}-5{{x}^{3}} &=-3 \\\\ \\left( 5{{x}^{3}}-5{{x}^{3}} \\right)+\\left( -4{{x}^{2}}+4{{x}^{2}} \\right)+\\left( 2x-x \\right)+\\left( -1+3 \\right) &=-3 \\\\ 0+0+x+2 &=-3 \\\\ x+2 &=-3 \\\\ x &=-5 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-5$.<\/span><\/span>"}]}],"id_ques":1230},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" <span class='basic_left'> Cho c\u00e1c \u0111a th\u1ee9c: <br\/> $M=-2{{x}^{4}}-7x+\\dfrac{1}{2}-6{{x}^{4}}+2{{x}^{2}}-x $ <br\/> $ N=3{{x}^{3}}-{{x}^{4}}-5{{x}^{2}}+{{x}^{3}}-6x+\\dfrac{3}{4}$ <br\/> T\u00ednh $M+N$ v\u00e0 t\u00ecm h\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c. <br\/> H\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c l\u00e0: <\/span>","select":["A. $4$","B. $-14$","C. $-9$","D. $-3$"],"explain":"<span class='basic_left'>Ta c\u00f3: <br\/> $\\begin{align}& M+N=\\left( -2{{x}^{4}}-7x+\\dfrac{1}{2}-6{{x}^{4}}+2{{x}^{2}}-x \\right)+\\left( 3{{x}^{3}}-{{x}^{4}}-5{{x}^{2}}+{{x}^{3}}-6x+\\dfrac{3}{4} \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=-2{{x}^{4}}-7x+\\dfrac{1}{2}-6{{x}^{4}}+2{{x}^{2}}-x+3{{x}^{3}}-{{x}^{4}}-5{{x}^{2}}+{{x}^{3}}-6x+\\dfrac{3}{4} \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\left( -2{{x}^{4}}-6{{x}^{4}}-{{x}^{4}} \\right)+\\left( 3{{x}^{3}}+{{x}^{3}} \\right)+\\left( 2{{x}^{2}}-5{{x}^{2}} \\right)+\\left( -7x-x-6x \\right)+\\left( \\dfrac{1}{2}+\\dfrac{3}{4} \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=-9{{x}^{4}}+4{{x}^{3}}-3{{x}^{2}}-14x+\\dfrac{5}{4} \\\\ \\end{align}$ <br\/> L\u0169y th\u1eeba cao nh\u1ea5t c\u1ee7a bi\u1ebfn l\u00e0 $4$ n\u00ean h\u1ec7 s\u1ed1 cao nh\u1ea5t l\u00e0 $-9$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span>","column":4}]}],"id_ques":1231},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["f","f","t"]],"list":[{"point":5,"image":"","col_name":["Cho hai \u0111a th\u1ee9c: <br\/> $A=5-2{{x}^{3}}+\\dfrac{1}{4}{{x}^{2}} $ <br\/> $ B=-\\dfrac{3}{4}{{x}^{2}}+{{x}^{3}}+5+x$ ","\u0110\u00fang","Sai"],"arr_ques":[" $A+B=-3{{x}^{3}}-\\dfrac{1}{2}{{x}^{2}}+x+10$ ","H\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c t\u1ed5ng $A+B$ l\u00e0 $-3$","B\u1eadc c\u1ee7a \u0111a th\u1ee9c t\u1ed5ng $A+B$ l\u00e0 $3$"],"hint":"","explain":[" <span class='basic_left'>Sai, v\u00ec <br\/> $\\begin{align} & A+B=\\left( 5-2{{x}^{3}}+\\dfrac{1}{4}{{x}^{2}} \\right)+\\left( -\\dfrac{3}{4}{{x}^{2}}+{{x}^{3}}+5+x \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=5-2{{x}^{3}}+\\dfrac{1}{4}{{x}^{2}}-\\dfrac{3}{4}{{x}^{2}}+{{x}^{3}}+5+x \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\left( -2{{x}^{3}}+{{x}^{3}} \\right)+\\left( \\dfrac{1}{4}{{x}^{2}}-\\dfrac{3}{4}{{x}^{2}} \\right)+x+\\left( 5+5 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=-{{x}^{3}}-\\dfrac{1}{2}{{x}^{2}}+x+10 \\\\ \\end{align}$ <\/span>"," <br\/> <span class='basic_left'>Sai, v\u00ec <br\/> $A+B=-{{x}^{3}}-\\dfrac{1}{2}{{x}^{2}}+x+10$ (theo c\u00e2u tr\u00ean) <br\/> Do \u0111\u00f3, h\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c t\u1ed5ng $A+B$ l\u00e0 $-1$<\/span> ","<br\/> <span class='basic_left'>\u0110\u00fang, v\u00ec <br\/> $A+B=-{{x}^{3}}-\\dfrac{1}{2}{{x}^{2}}+x+10$ (theo c\u00e2u tr\u00ean) <br\/> Do \u0111\u00f3, b\u1eadc c\u1ee7a \u0111a th\u1ee9c t\u1ed5ng $A+B$ l\u00e0 $3$<\/span>"]}]}],"id_ques":1232},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" <span class='basic_left'> X\u00e1c \u0111\u1ecbnh \u0111a th\u1ee9c b\u1eadc nh\u1ea5t $P(x)=ax+b$ bi\u1ebft r\u1eb1ng $P(-1)=5$ v\u00e0 $P(-2)=7$ <\/span>","select":["A. $P(x)=6x+8 $","B. $P(x)=-3x+5$","C. $P(x)=12x+17$","D. $P(x)=-2x+3$"],"explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> T\u00ecm hai bi\u1ec3u th\u1ee9c li\u00ean h\u1ec7 gi\u1eefa $a$ v\u00e0 $b$ t\u1eeb $P(-1)=5$ v\u00e0 $P(-2)=7$ <br\/> T\u1eeb hai bi\u1ec3u th\u1ee9c li\u00ean h\u1ec7 \u0111\u00f3 bi\u1ebfn \u0111\u1ed5i \u0111\u1ec3 t\u00ecm ra $a$ v\u00e0 $b$ <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Ta c\u00f3: <br\/> $\\begin{align} & P\\left( -1 \\right)=5 \\\\ & \\Rightarrow 5=a.\\left( -1 \\right)+b \\\\ & \\Rightarrow -a+b=5 \\\\ & \\Rightarrow a-b=-5\\,\\,\\,\\,\\,\\left( 1 \\right) \\\\ \\end{align}$ <br\/> V\u00e0: <br\/> $\\begin{align} & P\\left( -2 \\right)=7 \\\\ & \\Rightarrow 7=a.\\left( -2 \\right)+b \\\\ & \\Rightarrow -2a+b=7 \\\\ & \\Rightarrow 2a-b=-7\\,\\,\\,\\,\\left( 2 \\right) \\\\ \\end{align}$ <br\/> T\u1eeb (1) ta c\u00f3: $a=b-5$ <br\/> Thay $a=b-5$ v\u00e0o (2) ta \u0111\u01b0\u1ee3c: <br\/> $\\begin{align} & 2\\left( b-5 \\right)-b=-7 \\\\ & \\Rightarrow 2b-10-b=-7 \\\\ & \\Rightarrow b-10=-7 \\\\ & \\Rightarrow b=10-7=3 \\\\ & \\Rightarrow a=b-5=3-5=-2 \\\\ \\end{align}$ <br\/> V\u1eady \u0111a th\u1ee9c c\u1ea7n t\u00ecm l\u00e0 $P(x)=-2x+3$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span>","column":2}]}],"id_ques":1233},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["0,2"]]],"list":[{"point":5,"width":40,"content":"","ques":"Cho \u0111a th\u1ee9c sau: <br\/> $P\\left( x \\right)=7,4x-8-\\left[ -5,6x+\\left( -2,4x+7 \\right)-11,92 \\right]$ <br\/> \u0110\u1ec3 $P(x)=0$ th\u00ec gi\u00e1 tr\u1ecb c\u1ee7a $x$ l\u00e0 _input_","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>R\u00fat g\u1ecdn \u0111a th\u1ee9c $P(x)$ <br\/> Cho $P(x)=0$ r\u1ed3i t\u00ecm $x$ <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/> $\\begin{align} & P\\left( x \\right)=7,4x-8-\\left[ -5,6x+\\left( -2,4x+7 \\right)-11,92 \\right] \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=7,4x-8-\\left(-5,6x-2,4x+7-11,92 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=7,4x-8-\\left(-8x-4,92 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=7,4x-8+8x+4,92 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\left( 7,4x+8x \\right)+\\left( -8+4,92 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=15,4x-3,08 \\\\ \\end{align}$ <br\/> \u0110\u1ec3 $P(x)=0$ ta c\u00f3: <br\/> $\\begin{align} 15,4x-3,08 &=0 \\\\ 15,4x &=3,08 \\\\ x &=3,08:15,4=0,2 \\\\ \\end{align}$<\/span>"}]}],"id_ques":1234},{"time":24,"part":[{"title":"Ch\u1ecdn <u>nh\u1eefng<\/u> \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"Ch\u1ecdn \u0111\u01b0\u1ee3c nhi\u1ec1u \u0111\u00e1p \u00e1n","temp":"checkbox","correct":[["3","4"]],"list":[{"point":5,"img":"","ques":" Trong c\u00e1c gi\u00e1 tr\u1ecb sau, gi\u00e1 tr\u1ecb n\u00e0o l\u00e0 nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $P(x)=6x^2-7x-3$?","hint":"","column":2,"number_true":2,"select":["A. $2$","B. $-3$","C. $\\dfrac{3}{2}$","D. $-\\dfrac{1}{3}$"],"explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ \u1edf m\u1ed7i \u0111\u00e1p \u00e1n \u0111\u00e3 cho v\u00e0o \u0111a th\u1ee9c $P(x)$ <br\/> Gi\u00e1 tr\u1ecb n\u00e0o th\u1ecfa m\u00e3n $P(x)=0$ th\u00ec \u0111\u00f3 l\u00e0 nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $P(x)$<br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $\\bullet $ Thay $x=2$ v\u00e0o $P(x)$ ta c\u00f3: <br\/> $6x^2-7x-3=6.2^2-7.2-3=7 \\ne 0$ <br\/> $\\Rightarrow x=2$ kh\u00f4ng ph\u1ea3i nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $P(x)$ <br\/> $\\bullet $ Thay $x=3$ v\u00e0o $P(x)$ ta c\u00f3: <br\/> $6x^2-7x-3=6.3^2-7.3-3=30 \\ne 0$ <br\/> $\\Rightarrow x=3$ kh\u00f4ng ph\u1ea3i nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $P(x)$ <br\/> $\\bullet $ Thay $x=\\dfrac{3}{2}$ v\u00e0o $P(x)$ ta c\u00f3: <br\/> $6x^2-7x-3=6.{{\\left( \\dfrac{3}{2} \\right)}^{2}}-7.\\dfrac{3}{2}-3=0$ <br\/> $\\Rightarrow x=\\dfrac{3}{2}$ l\u00e0 m\u1ed9t nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $P(x)$ <br\/> $\\bullet $ Thay $x=-\\dfrac{1}{3}$ v\u00e0o $P(x)$ ta c\u00f3: <br\/> $6x^2-7x-3=6.{{\\left( -\\dfrac{1}{3} \\right)}^{2}}-7.\\left( -\\dfrac{1}{3} \\right)-3=0 $ <br\/> $\\Rightarrow x=-\\dfrac{1}{3}$ l\u00e0 m\u1ed9t nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $P(x)$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n ch\u1ecdn l\u00e0 C v\u00e0 D.<\/span><\/span>"}]}],"id_ques":1235},{"time":24,"part":[{"title":"N\u1ed1i m\u1ed9t nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c \u1edf c\u1ed9t ph\u1ea3i t\u01b0\u01a1ng \u1ee9ng v\u1edbi \u0111a th\u1ee9c \u0111\u00e3 cho \u1edf c\u1ed9t tr\u00e1i","title_trans":"","audio":"","temp":"matching","correct":[["1","3","4","2"]],"list":[{"point":5,"image":"","left":["$P(x)=2x+1$","$Q(x)=5-2x$","$H(x)=\\dfrac{1}{3}x-2$","$G(x)=7x+3$"],"right":["$-\\dfrac{1}{2}$","$-\\dfrac{3}{7}$ ","$\\dfrac{5}{2}$","$6$"],"top":100,"hint":"","explain":" <span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{aligned} & \\begin{matrix} \\begin{aligned} & \\bullet \\,\\,\\,P\\left( x \\right)=0 \\\\ & \\Rightarrow 2x+1=0 \\\\ & \\Rightarrow 2x=-1 \\\\ & \\Rightarrow x=-\\dfrac{1}{2} \\\\ \\end{aligned} & \\begin{aligned} & \\bullet \\,Q\\left( x \\right)=0 \\\\ & \\Rightarrow 5-2x=0 \\\\ & \\Rightarrow -2x=-5 \\\\ & \\Rightarrow x=\\dfrac{5}{2} \\\\ \\end{aligned} \\\\\\end{matrix} \\\\ & \\begin{matrix} \\begin{aligned}& \\bullet \\,H\\left( x \\right)=0 \\\\ & \\Rightarrow \\dfrac{1}{3}x-2=0 \\\\ & \\Rightarrow \\dfrac{1}{3}x=2 \\\\ & \\Rightarrow x=2:\\dfrac{1}{3}=6 \\\\ \\end{aligned} & \\begin{aligned} & \\bullet \\,G\\left( x \\right)=0 \\\\ & \\Rightarrow 7x+3=0 \\\\ & \\Rightarrow 7x=-3 \\\\ & \\Rightarrow x=-\\dfrac{3}{7} \\\\ & \\\\ & \\\\ \\end{aligned} \\\\\\end{matrix} \\\\ \\end{aligned}$ <\/span> "}]}],"id_ques":1236},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y \u0110\u00fang hay Sai","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" \u0110a th\u1ee9c $G(x)=x^2+1$ kh\u00f4ng c\u00f3 nghi\u1ec7m. ","select":["\u0110\u00fang","Sai"],"explain":"<span class='basic_left'> Ta c\u00f3: $x^2 \\ge 0 \\Rightarrow x^2+1 \\ge 1$ v\u1edbi m\u1ecdi $x$ <br\/> Do \u0111\u00f3 $G(x)=x^2+1 \\ne 0$ v\u1edbi m\u1ecdi $x$ <br\/> \u0110a th\u1ee9c $G(x)=x^2+1$ kh\u00f4ng c\u00f3 nghi\u1ec7m. <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 \u0110\u00fang.<\/span> <\/span>","column":2}]}],"id_ques":1237},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" <span class='basic_left'> S\u1ed1 nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $H(x)=x^2-25$ l\u00e0: <\/span>","select":["A. $0 $","B. $1$","C. $2$"],"explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{aligned} & \\,\\,\\,\\,H\\left( x \\right)=0 \\\\ & \\Rightarrow {{x}^{2}}-25=0 \\\\ & \\Rightarrow {{x}^{2}}=25 \\\\ & \\Rightarrow \\left[ \\begin{aligned} & x=5 \\\\ & x=-5 \\\\ \\end{aligned} \\right. \\\\ \\end{aligned}$. <br\/> \u0110a th\u1ee9c $H(x)=x^2-25$ c\u00f3 hai nghi\u1ec7m l\u00e0 $5$ v\u00e0 $-5$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span>","column":3}]}],"id_ques":1238},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y \u0110\u00fang hay Sai","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" <span class='basic_left'> X\u00e9t \u0111a th\u1ee9c $P(x)=ax^2+bx+c$ <br\/> N\u1ebfu $a+b+c=0$ th\u00ec $P(x)$ c\u00f3 m\u1ed9t nghi\u1ec7m l\u00e0 $x=1$<\/span> ","select":["\u0110\u00fang","Sai"],"explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> Ki\u1ec3m tra xem $x=1$ c\u00f3 th\u1ecfa m\u00e3n $P(x)=0$ kh\u00f4ng? <br\/> Thay $x=1$ v\u00e0o \u0111a th\u1ee9c $P(x)$ <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Thay $x=1$ v\u00e0o \u0111a th\u1ee9c $P(x)$ ta \u0111\u01b0\u1ee3c: <br\/> $a.1^2+b.1+c=a+b+c=0$ <br\/> Do \u0111\u00f3 $x=1$ l\u00e0 nghi\u1ec7m c\u1ee7a $P(x)$ n\u1ebfu $a+b+c=0$.<br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 \u0110\u00fang.<\/span> <\/span>","column":2}]}],"id_ques":1239},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y \u0110\u00fang hay Sai","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" <span class='basic_left'> X\u00e9t \u0111a th\u1ee9c $P(x)=ax^2+bx+c$ <br\/> N\u1ebfu $a-b+c=0$ th\u00ec $P(x)$ c\u00f3 m\u1ed9t nghi\u1ec7m l\u00e0 $x=-1$<\/span> ","select":["\u0110\u00fang","Sai"],"explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> Ki\u1ec3m tra xem $x=-1$ c\u00f3 th\u1ecfa m\u00e3n $P(x)=0$ kh\u00f4ng? <br\/> Thay $x=-1$ v\u00e0o \u0111a th\u1ee9c $P(x)$ <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Thay $x=-1$ v\u00e0o \u0111a th\u1ee9c $P(x)$ ta \u0111\u01b0\u1ee3c: <br\/> $a.(-1)^2+b.(-1)+c=a-b+c =0$ <br\/> Do \u0111\u00f3 $x=-1$ l\u00e0 nghi\u1ec7m c\u1ee7a $P(x)$ n\u1ebfu $a-b+c=0$.<br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 \u0110\u00fang.<\/span> <\/span>","column":2}]}],"id_ques":1240}],"lesson":{"save":0,"level":2}}